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sineoko [7]
4 years ago
10

(Pls do solution or take picture)In the figure, ACEF is a rectangle and BC = CD DE The area of rectangle ACEF is 80 cm. Find the

area of the triangle BDF.​

Mathematics
1 answer:
poizon [28]4 years ago
6 0

Answer:

28 cm²

Step-by-step explanation:

The area of Δ BDF is the area of the rectangle subtract the area of the 3 white triangles.

Since the area of the rectangle = 80 cm² and

area = length × breadth, then

breadth = 80 ÷ 10 = 8 cm

Thus CE = EF = 8 cm and CD = DE = BC = 4 cm

Area of Δ DEF = 0.5 × 10 × 4 = 20 cm²

Area of Δ ABF = 0.5 × 8 × (10 - 4) = 0.5 × 8 × 6 = 24 cm²

Area of Δ BCD = 0.5 × 4 × 4 = 8 cm²

Thus

area of Δ BDF = 80 - (20 + 24 + 8) = 80 - 52 = 28 cm²

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Answer:

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3 years ago
1)The graph below shows a line segment XY:
Hitman42 [59]
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4 years ago
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Write the slope-intercept form of the equation of each line.
shtirl [24]

Answer:

12) y = -x + 8

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Step-by-step explanation:

12)

y - 4 = −(x - 4)

y - 4 = −x + 4

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_______________________________________________

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10)

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Answer:

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Step-by-step explanation:

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konstantin123 [22]

Answer:

x=2

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you get -10x=-20

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6 0
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