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3 years ago

One and six tenths as a decimal

Mathematics

2 answers:

natita [175]3 years ago

4 0

Answer:

1.6

Step-by-step explanation:

1 and 6 tenths = 1.6

One-tenth = 1/10 = 0.1

6 tenths: 6 × 0.1 = 0.6

1 and six tenths:

1 + 0.6

1.6

PilotLPTM [1.2K]3 years ago

3 0

Answer:

1.6

Step-by-step explanation:

first divide 6 by ten then add the one in the front

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3 years ago

Write 2^40 as an exponent with a base of: a 2^2; b 2^5; c 2^8; 2^10

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

Substitute the value of the variable into the expression and simplify.

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4 years ago

Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

$x=\frac{83}{50}$

Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

$m_A_B=-\frac{22}{15(x-1)}$

step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

$m_A_B=m_A_C$

$-\frac{22}{15(x-1)}=-\frac{20}{9}$

solve for x

$15(x-1)20=22(9)$

$300x-300=198$

$300x=198+300$

$300x=498$

$x=\frac{498}{300}$

simplify

$x=\frac{83}{50}$

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4 years ago

Write each phrase as an algebraic expression.<br> 16 seconds faster than Aya’s time.

Anna35 [415]

Given:

The given phrase is 16 seconds faster than Aya’s time.

To find:

The algebraic expression for the given phrase.

Solution:

Let x be the Aya’s time.

16 seconds faster than Aya’s time. It means 16 seconds less than Aya’s time.

We know that a negative sign "-" is used for less than.

16 seconds less than Aya’s time = $x-16$

16 seconds faster than Aya’s time = $x-16$

Therefore, the required algebraic expression is $x-16$ .

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3 years ago