Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
Answer:
0
Step-by-step explanation:
Y2-y1/x2-x1
5-5/9-10 =0/-1. Slope is 0
It costs 5,5! Bc 1 costs 0,5
Answer:
46
Step-by-step explanation:
Answer: 10%
Step-by-step explanation:
The difference between his estimated and actual distance is 15 - 13.5 = 1.5
The percentage of error is the difference divided by the actual value.
1.5÷15 = 0.10
Converted to a percentage, it is 10%