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Murljashka [212]
3 years ago
12

consider the conjecture "if the sum of the digits of a number is divisible by 9, then the number itself is divisible by 9." is t

he conjecture true?
Mathematics
1 answer:
den301095 [7]3 years ago
3 0
Yes
54_ 5+4=9           9/9=1      54/9=6
27_ 2+7=9           9/9=1      27/9=3
126_ 12+6=18    18/9=2    126/9=14
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The intensity of light with wavelength λ traveling through a diffraction grating with N slits at an angle θ is given by I(θ) = N
Ymorist [56]

Answer:

0.007502795

Step-by-step explanation:

We have

N = 10,000

\bf d=10^{-4}

\bf \lambda = 632.8*10^{-9}

Replacing these values in the expression for k:

\bf k=\frac{\pi Ndsin\theta}{\lambda}=\frac{\pi10^4*10^{-4}sin\theta}{632.8*10^{-9}}=\frac{\pi 10^9sin\theta}{632.8}

So, the intensity is given by the function

\bf I(\theta)=\frac{N^2sin^2(k)}{k^2}=\frac{10^8sin^2(\frac{\pi 10^9sin\theta}{632.8})}{(\frac{\pi 10^9sin\theta}{632.8})^2}

The <em>total light intensity</em> is then

\bf \int_{-10^{-6}}^{10^{-6}} I(\theta)d\theta=\int_{-10^{-6}}^{10{-6}}\frac{10^8sin^2(\frac{\pi 10^9sin\theta}{632.8})}{(\frac{\pi 10^9sin\theta}{632.8})^2}d\theta

Since \bf I(\theta) is an <em>even function</em>

\bf \int_{-10^{-6}}^{10^{-6}} I(\theta)d\theta=2\int_{0}^{10^{-6}}I(\theta)d\theta

and we only have to divide the interval \bf [0,10^{-6}] in five equal sub-intervals \bf I_1,I_2,I_3,I_4,I_5 with midpoints \bf m_1,m_2,m_3,m_4,m_5

The sub-intervals and their midpoints are

\bf I_1=[0,\frac{10^{-6}}{5}]\;,m_1=10^{-5}\\I_2=[\frac{10^{-6}}{5},2\frac{10^{-6}}{5}]\;,m_2=3*10^{-5}\\I_3=[2\frac{10^{-6}}{5},3\frac{10^{-6}}{5}]\;,m_3=5*10^{-5}\\I_4=[3\frac{10^{-6}}{5},4\frac{10^{-6}}{5}]\;,m_4=7*10^{-5}\\I_5=[4\frac{10^{-6}}{5},10^{-6}]\;,m_5=9*10^{-5}

<em>By the midpoint rule</em>

\bf \int_{0}^{10^{-6}}I(\theta)d\theta\approx\frac{10^{-6}}{5}[I(m_1)+I(m_2)+...+I(m_5)]

computing the values of I:

\bf I(m_1)=I(10^{-5})=\frac{10^8sin^2(\frac{\pi 10^9sin(10^{-5})}{632.8})}{(\frac{\pi 10^9sin(10^{-5})}{632.8})^2}=13681.31478

\bf I(m_2)=I(3*10^{-5})=\frac{10^8sin^2(\frac{\pi 10^9sin(3*10^{-5})}{632.8})}{(\frac{\pi 10^9sin(3*10^{-5})}{632.8})^2}=4144.509447

Similarly with the help of a calculator or spreadsheet we find

\bf I(m_3)=3.09562973\\I(m_4)=716.7480066\\I(m_5)=211.3187228

and we have

\bf \int_{0}^{10^{-6}}I(\theta)d\theta\approx\frac{10^{-6}}{5}[I(m_1)+I(m_2)+...+I(m_5)]=\frac{10^{-6}}{5}(18756.98654)=0.003751395

Finally the the total light intensity

would be 2*0.003751395 = 0.007502795

8 0
3 years ago
Can you help me with #7
Alex_Xolod [135]
2 miles-12 min.
3 miles- 18min
4 miles-24 min
5 miles-30 min

3 miles- 18
4 miles-24
5 miles-30
6 miles-36

Yes they are the same
7 0
3 years ago
Select the best estimate for the diameter of a dinner plate. A. 25 mm B. 25 cm C. 2,500 mm D. 25 m
natima [27]

Answer:

the best estimate is 25 cm

Step-by-step explanation:

the best estimate is 25 cm

because A would be too small

C too long

D way too much

8 0
3 years ago
Please help!
Ahat [919]
The vertical asymptote is r = 0.
The intensity is undefined at the source.
The horizontal asymptote is I = 0.
As the distance from the source increases, the intensity goes to zero.
The intensity decreases as the distance increases.
6 0
3 years ago
Read 2 more answers
(-5)x (-5) x (-5) x (-5) = <br> What would the answer be <br><br> 20 points
Natasha_Volkova [10]

Answer:

625x^{3}

Step-by-step explanation:

4 0
3 years ago
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