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-Dominant- [34]
3 years ago
12

What is a rectangular prism with a surface area of 96 square meters

Mathematics
2 answers:
goldenfox [79]3 years ago
8 0
If you're asking for the measurements, they are...

Length (l) = 4 ft.
Width (w) = 4 ft.
Height (h) = 4 ft.
mrs_skeptik [129]3 years ago
5 0

Answer:

Rectangular prism is a square prism with side = 4 meters

Step-by-step explanation:

A rectangular prism with a surface area = 96 square meters

Means 2(length×width + height×width + length×height) = 96

One possible solution is when length = width = height

2×3×side² = 96

6 × side² = 96

side² = 96/6 = 16

side = 4

Therefore length = width = height = 4 meters.

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8x + y = -39<br> 2x - 5y = 27<br> Solve the system by elimination
Ahat [919]

Answer:

(-4, -7)

Step-by-step explanation:

21y=-147

y=-7

2x-5x(-7)=27

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5 0
3 years ago
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

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Answer:

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