Let the angle of elevation is x and the height of the rocket from the ground is y
tanx = y/15
by differentiating both sides with respect to T
sec²x·dx/dt = (dy/dt)/15
at y = 30 , the hypotenuse of the triangle = 15√5
sec²x=(15√5/15)²=5
5 dx/dt = 11/15
dx/dt = 11/75 rad/sec
Answer:
C = 1.5W
Step-by-step explanation:
Weight: W
Cost: C
C = kW
15 = k(10)
k = 1.5
C = 1.5W
- if you simplify it you would have to find factors of 45 that are perfect squares, for example, the square root of 9 times the square root of 5 is the square root of 45 so if you want to simplify it you would need to take the square root of 9 which is 3
so if you put in simplest form you would get 3 root 5

I've attached the correct image to this answer, just in case they're scrambled.