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3 years ago

ALGEBRA EQUATION PLEASE HELP ASAP -3=12y-5(2y-7)

2 answers:

5 0

-3 = 12y -5(2y-7)

-3 = 12y +(-5)*2y + (-5)*(-7)

-3 = 12y -10y + 35

-3 = 2y +35

2y= -3 -35

2y = -38

Therefore:

y=-19

As 2*(-19) = -38

Dovator [93]3 years ago

3 0

Simplify:

−3=12y−5(2y−7)

−3=12y+(−5)(2y)+(−5)(−7)(Distribute)

−3=12y+−10y+35

−3=(12y+−10y)+(35)(Combine Like Terms)

−3=2y+35

Flip the equation.

2y+35=−3

Subtract 35 from both sides.

2y+35−35=−3−35

2y=−38

Divide both sides by 2.

2y/2=−38/2

y=−19

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X>y <br><br>Which is greater? x+a or y+a urgent please?!

earnstyle [38]

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4 0

4 years ago

Read 2 more answers

The first term of an Ap is - 504 while<br>the sum of its 9 terms is-126 find<br>Sum of its 30 terms

frozen [14]

Answer:

The sum of its 30 terms is 38167.5

Step-by-step explanation:

Given:

The First term in the AP is -504

The Sum of its 9 terms is -126

To Find:

The sum of its 30 terms = ?

Solution:

The sum of n terms of an AP:

$S_n = (\frac{n}{2} ) [ 2 a_1 + ( n - 1 ) d ]$

The sum of 9 terms of an AP:

$S_9 = (\frac{9 }{2} ) [ 2(-504) + ( 9 - 1 )d ]$

$S_9 = (4.5 )[ 2 (-504)+ ( 8 ) d ]$

$(4.5 )(2)(-504) + (4.5) 8 d = - 126$

(-4536) +36d = -126

36 d = -126+4536

36 d= 4410

$d= \frac{4410}{36}$

d = 122.5

The sum of its 30 terms is

$S_{30} = ( \frac{30 }{2 }) [ 2 (-504) + ( 30-1)(122.5) ]$

$S_{30} =(15) [ 2 (-504) + ( 29)(122.5) ]$

$S_{30} = [ 2 (-504)(15) + ( 29)(122.5)(15) ]$

$S_{30} = [ -15120 + 53287.5 ]$

$s_{30} = 38.167.5$

6 0

4 years ago

How do you add negative numbers with positives

Strike441 [17]

when we add negative number to the positive number we just subtract the smaller number from the larger number and put the sign or the larger number after words

examples:- First

$5 + ( - 2) = 5 - 2 = 3$