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3 years ago

Simplify the following expression. 5(x + y) + 3(x - y)

1 answer:

4 0

It could also be written as
5x+5y+3x-3y when you merge the factors
from here you could add like terms
5x+3x+5y-3y
8x+2y would be your final answer since x and y aren't like terms therefore it cannot be reduced further

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Find the domains of the following expressions: 5/the square root of 5-5x

AleksandrR [38]

Interval notation

(-infinity sign, 1)

Set-builder notation

{x|x less than equal to 1}

7 0

3 years ago

The last rest area you spent $3.25 on water bottles, $11.00 on snacks, and $4.00 on a magazine, and gave the cashier $20.00 How

photoshop1234 [79]

Answer:

You spent 18.25, and got 1.75 in change

Step-by-step explanation:

3.25 + 11 + 4 = 18.25

20.00 - 18.25 = 1.75

6 0

2 years ago

Read 2 more answers

To make a trail mix you must have 4 cups of pretzels and 2 cups of bread chips.What is the ratio of pretzels to bread chips?

WINSTONCH [101]

4:2 which can be converted to 2:1

3 0

3 years ago

Henry's baseball practice starts at 2:00 pm. It lasts 1 hour and 45 minutes. What time does he get out of baseball practice? Wri

tresset_1 [31]

Answer:

Henry's baseball practice starts at 2:00, will last an hour and forty-five minutes, and will end at 3:45.

Step-by-step explanation:

2 + 1 = 3

3 + 45 minutes = 3 : 45

8 0

2 years ago

A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs

LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

$h=\frac{400}{\pi r^2}$

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: $h=\frac{400}{\pi r^2}$

Therefore:

$C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})$

$C(r)=0.12\pi r^2+\frac{24}{r}$

$C(r)=\frac{0.12\pi r^3+24}{r}$

The minimum cost occurs when the derivative of the Cost =0.

$C^{'}(r)=\frac{6\pi r^3-600}{25r^2}$

$6\pi r^3-600=0$

$6\pi r^3=600$

$\pi r^3=100$

$r^3=\frac{100}{\pi}$

$r^3=31.83$

r=3.17 cm

Recall that:

$h=\frac{400}{\pi r^2}$

$h=\frac{400}{\pi *3.17^2}$

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0

3 years ago