Question

Please help this is due?? I will give brainliest

Answer 1

Answer:

The Supersmack gum has a volume of $V=6.75\pi$ cm^3 or $V=21.2057$ cm^3. So, Supersmack's cylindrical bubble gum has more actual gum than the Megapop gumball

Step-by-step explanation:

Assuming that the radius of the Megapop gumball is 1.5 (the same diameter as Supersmack)

The volume of the cylinder's equation can be written as

$V=\pi (1.5^{2})(3 )$

This simplifies to

$V=6.75\pi$ cm^3 or $V=21.2057$ cm^3

The volume of the gumball's equation can be written as

$V=\frac{4}{3} \pi (1.5)^{3}$

This simplifies to

$v=4.5\pi$ cm^3 or $V=14.1371$ cm^3

The Supersmack gum has a volume of $V=6.75\pi$ cm^3 or $V=21.2057$ cm^3. So, Supersmack's cylindrical bubble gum has more actual gum than the Megapop gumball