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WITCHER [35]
3 years ago
5

Can someone help I have to hand this in

Mathematics
2 answers:
Mrrafil [7]3 years ago
6 0

Answer:#1

Step-by-step explanation:

Ludmilka [50]3 years ago
3 0
It’s 1................
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Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

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Step-by-step explanation:

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The second fractions has a demoninator of 8 bc u already took one from the bag and didnt return it

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