Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Certin, because they can be any two cards.
Answer:
If X=2 then the equation would be solved starting with 8x2=16 then take 16 and subtract it by 7 which would equal 9, then you take 9 and add 5 to it and that would give you the answer of 14
Step-by-step explanation:
(8x-7)+5 x=2
(8x2-7)+5
(16-7)+5
9+5
<u>Answer 14</u>
I hope this helps you
74% is grater hope i helped
Answer:
8 - p
Step-by-step explanation:
X is p fewer than Y … X = Y - P
