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Artemon [7]
3 years ago
6

How do you do y=-1/2x+7 5x-2y=10​

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

Solve with system of equations

answer is (4,5)

You would graph (4,5)

x=4 and y=5

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There are 4 triangles and 16 squares.what is the simplest ratio of triangles to square
brilliants [131]
1:4
The ratio of triangles to squares is 4:16 unsimplified because there are 4 triangles and 16 squares. To simplify the ratio, think of it as a fraction:
4/16
The fraction can be simplified to 1/4, meaning that the simplest ratio is 1:4.
5 0
3 years ago
What is y-7=8?one step equation
vodomira [7]

Answer:

y=15

Step-by-step explanation:

y-7=8

Add 7 to each side to cancel out the 7 next to the variable.

You get y=15.

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3 years ago
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What is the definition of present value?
Bezzdna [24]

Answer:

the value in the present of a sum of money, in contrast to some future value it will have when it has been invested at compound interest.

Step-by-step explanation:

6 0
3 years ago
Plz solve it is ergent <br>​
soldier1979 [14.2K]

Answer:

first term = 2 ...(given)

second term = f (2) = f (2-1) * 5 = 1 * 5 = 5. .....[according to the formula f(n) = f (n -1) *5 ]

third term = f (3) = f ( 3 - 1 ) * 5 = 2 * 5 = 10

fourth term = f (4) = f (4 - 1) * 5 = 3 * 5.= 15

fivth term = f (5) = f ( 5 - 1) * 5 = 4* 5. =20

7 0
3 years ago
Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t
andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ.e^{-\lambda.x}

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - e^{-\lambda.x}

(a) <u>Probability</u> of distance at most <u>100m</u>, with λ = 0.0143:

F(100) = 1 - e^{-0.0143.100}

F(100) = 0.76

<u>Probability</u> of distance at most <u>200</u>:

F(200) = 1 - e^{-0.0143.200}

F(200) = 0.94

<u>Probability</u> of distance between <u>100 and 200</u>:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = \frac{1}{\lambda}

E(X) = \frac{1}{0.0143}

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = \sqrt{\frac{1}{\lambda^{2}} }

σ = \sqrt{\frac{1}{0.0143^{2}} }

σ = 69.93

<u>Distance exceeds the mean distance by more than 2σ</u>:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - e^{-0.0143*209.79})

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

\int\limits^m_0 f({x}) \, dx = 0.5

\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx = 0.5

\lambda.\frac{e^{-\lambda.x}}{-\lambda} = -e^{-\lambda.x} + e^{0}

1 - e^{-\lambda.m} = 0.5

-e^{-\lambda.m} = - 0.5

ln(e^{-0.0143.m}) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0
4 years ago
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