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Artemon [7]
3 years ago
6

How do you do y=-1/2x+7 5x-2y=10​

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

Solve with system of equations

answer is (4,5)

You would graph (4,5)

x=4 and y=5

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If every dimension of a two-dimensional figure is multiplied by k, by what quantity is the area multiplied?
Igoryamba
For example: Square has dimension a
A = a²  and if every dimension is multiplied by k new dimension would be:
A 1 = k² a² = k² A.
Or the area of rhombus: A = d1 * d 2 / 2
New area is: A 1 = k d 1 * k d 2 / 2 =  k² A
Answer: If every dimension of two-dimensional figure is multiplied by k, the area is multiplied by k².
8 0
3 years ago
Many people are surprised to find that math is found in the Bible in many places. God created all things and sustains all things
uranmaximum [27]

Answer:

Solid 1:

T.A. = 2(wl + hl + hw)

T.A. = 2(2 * 8 + 4 * 8 + 4 * 2)

T.A. = 2(16 + 32 + 8)

T.A. = 32 + 64 + 16

T.A. = 96 + 16

T.A. = 112m^2

V = w * h * l

V = 2 * 4 * 8

V = 8 * 8

V = 64m^3

M = 0.003 * 64

M = $0.19

Solid 2:

T.A. = l sqr(l^2 + 4 * h^2) + l^2

T.A. = 6 sqr(6^2 + 4 * 5^2) + 6^2

T.A. = 106m^2

V = 1/3 * b * h

V = 1/3 * 36 * 5

V = 12 * 5

V = 60m^3

M = 0.003 * 60

M = $0.18

Solid 3:

T.A. = (2 * pi * r^2) + (2 * pi * r * h)

T.A. = (2 * pi * 2.5^2) + (2 * pi * 2.5 * 3.5)

T.A. = (2 * pi * 6.25) + (2 * pi * 2.5 * 3.5)

T.A. = 39.27 + 54.98

T.A. = 94.25m^2

V = pi * r^2 * h

V = pi * 2.5^2 * 3.5

V = pi * 6.25 * 3.5

V = pi * 21.88

V = 68.72m^3

M = 0.003 * 68.72

M = $0.21

Solid 4:

T.A. = pi * r^2 + pi * r * sqr(r^2 + h^2)

T.A. = pi * 4^2 + pi * 4 * sqr(4^2 + 6^2)

T.A. = pi * 16 + pi * 4 * sqr(16 + 36)

T.A. = 50.26 + 12.56 * sqr(52)

T.A. = 62.82 * sqr(52)

T.A. = 140.9m^2

V = 1/3 * pi * r^2 * h

V = 1/3 * pi * 4^2 * 6

V = 1/3 * pi * 16 * 6

V = 1/3 * pi * 96

V= pi * 32

V = 100.5m^3

M = 0.003 * 100.5

M = $0.30

Solid 5:

T.A. = 4 * pi * r^2

T.A. = 4 * pi * 2.6^2

T.A. = 4 * pi * 6.76

T.A. = pi * 27.04

T.A. = 84.95m^2

V = 4/3 * pi * r^3

V = 4/3 * pi * 2.6^3

V = 4/3 * pi * 17.576

V = pi * 23.434

V = 73.62m^3

M = 0.003 * 73.62

M = $0.22

Write a paragraph that answers the following questions:

● Do all of the solids hold between 60 and 70 cubic inches?

● Which solid is the most cost efficient (the packaging with the smallest materials cost that holds between 60 and 70 cubic inches)?

● Would the Ark be most cost efficient solid for packaging? Why or why not?

● Which solid would you recommend using? Why?

● Why do you think that God was very specific in the measurements that He gave Noah for the Ark? Be sure to use some of your findings from this project to support your answer.

Of the five shapes, only the rectangular prism, the square pyramid, and the cylinder held between 60 and 70 cubic inches. The square pyramid was the most cost efficient, holding a price of $0.18. A rectangular prism would not be the most efficient shape cost wise, however it would be sufficient to hold the materials. I think I would recommend the rectangular prism for this project, because it is the second most cost efficient and holds a greater volume for use. I think God gave Moses the exact plans needed to perfectly fit all his animals. I think he wanted to prove to Moses his power and knowledge by providing the exact amount needed. In this project I took the measurements and I used them to discover which was best suited to serve the purpose needed, but God already knew and used it as a lesson in faith for Moses.

Step-by-step explanation:

7 0
3 years ago
Find the value of x that makes the equation true:
uranmaximum [27]

Answer:

13

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
HELP
GREYUIT [131]
$750*.05 = $37.50 
$420*.05 =$21.00 

So the answer to your question would be C. At most $37.50 and at least $21.00 per month. 

Hope this helps! :) 

6 0
3 years ago
The side s of a square carpet is measured at 5 ft. Estimate using the Linear Approximation the maximum error in the area A of th
KonstantinChe [14]

Answer:

0.333 ft^2

Step-by-step explanation:

We are given that

Side of square carpet,s=5 ft

\Delta s=0.4 in=\frac{0.4}{12}ft

1 foot=12 in

We have to find the maximum error in the area of the carpet by using the linear approximation .

Area of square,A=(side)^2=s^2

dA=2sds

Substitute the values

dA=2\times 5\times \frac{0.4}{12}

dA=0.333ft^2

Hence, the maximum error in the area of the carpet=0.333 ft^2

4 0
3 years ago
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