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3 years ago

Which of the following ratios is equivalent to 49:35?

2 answers:

8 0

The best way to find it is to reduce each ratio you work with to its
lowest terms,and see which ones are equal. To reduce a ratio to its
lowest terms, divide each number by their greatest common factor.

First, the one that you're trying to match: 49:35 .
The greatest common factor of 49 and 35 is 7 .
Divide each number by 7 . . . 7:5 . . . that's what you have to match.

7:4
Their greatest common factor is ' 1 '.
No help at all, and this one is not it.

14:25
Again, their greatest common factor is '1 '.
No help at all, and this one is not it.

21:15
Their greatest common factor is ' 3 '.
Divide both numbers by 3 . . . 7:5 .
That's it !

nordsb [41]3 years ago

4 0

49=7*7
35=7*5
so 49:35=7*7:7*5=7:5
7:4 is not 7:5
14:25 also isn't 7:5
21:15=3*7:3*5=7:5
the answer is 21:15

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We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

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<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

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