Answer:
Step-by-step explanation:
We want to write the trignometric expression:
As an algebraic equation.
First, we can focus on the inner expression. Let θ equal the expression:
Take the secant of both sides:
Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:
By substitutition:
Using an double-angle identity:
We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:
Simplify. Therefore:
Coordinates of the given triangle ΔPQR P(1,-1), Q(3,-2), R(3,-4).
a) Let us discuss the rule for rotation of 90° clockwise about the origin.
If given coordinate is (h,k) is rotated 90° clockwise about the origin the position of rotated coordinate will be (k, -h).
x and y coordinates would switch their values and after switching x any values, the y value of the coordinates would reverse in sign.
So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become
P(1,-1) --> P'(-1,-1)
Q(3,-2) --> Q'( -2,-3)
R(3,-4) --> R'(-4,-3)
b) If given coordinate is (h,k), the coordinates after reflection across the x-axis would besome (h,-k). (Just change in the sign of y-coordinate).
So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become
P(1,-1) --> P"(1,1)
Q(3,-2) --> Q"( 3,2)
R(3,-4) --> R"(3,4)
