Find the slope of the line with the given equation. Show your work. 6x – 2y = 18

1 answer:

7 0

Currently the equation 6x - 2y = 18 is in standard form. Convert the standard form equation into a slope-intercept form and we can find the slope easily.

Solve for y.

6x - 2y = 18
-2y = 18 - 6x <-- Subtract 6x from each side. This is to isolate the 2y term
2y / -2 = $\frac{18 - 6x}{2}$ <-- Divide each side by 2. This it to
get rid of the 2 coefficient.
y = -9 + 3x

Rearrange the right-hand side a bit.

y = -9 + 3x becomes y = 3x - 9

Now it is in slope-intercept form.
The slope is the coefficient of the x variable.

So, 3 is the slope.

You might be interested in

The sum of two numbers is 52 . The larger number is 6 more than the smaller number. What are the numbers?

tester [92]

Answer:

the answer is 2

Step-by-step explanation:

52÷2=26

26÷2=13

3 0

3 years ago

SOMEONE HELP PLS 15 POINTS FOR ONE EASY MC QUESTION

Ksenya-84 [330]

Answer:

A rectangle could not be a cross section of a cylinder

could you help me with this: brainly.com/question/21423860

6 0

2 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$