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Brums [2.3K]
4 years ago
11

(10-6)^3•4^2+ (10+2)^2​

Mathematics
1 answer:
ValentinkaMS [17]4 years ago
8 0

Idk if the dot is multiplication or sth else

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Which best describes the transformation that occurs from the graph of f(x) = x2 to g(x) = (x + 3)2 + 4?
DIA [1.3K]

The answer would be A.  Left 3, up 4.

3 0
3 years ago
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Point B is a point of tangency. Find the radius r of OC.<br> А 9<br> B<br> r<br> n
insens350 [35]

Answer:

Radius, r, is 3.75

Step-by-step explanation:

From the given diagram,

AB = 9

AC = 6 + r

BC = r

Thus applying the Pythagoras theorem, we have;

/AC/^{2} = /AB/^{2} + /BC/^{2}

(6 + r)^{2} = 9^{2} + r^{2}

36 + 12r + r^{2} = 81 + r^{2}

collecting like terms,

12r = 81 - 36

12r = 45

r = \frac{25}{12}

   = 3.75

r = 3.75

The radius is 3.75.

3 0
3 years ago
The bookstore has six red school jerseys, five blue school jerseys, and ten green school jerseys to choose from. If a student se
slega [8]
Idkcczsnbzznnhdmsbdhsmmeyfhssfmgbhsngmfbd
3 0
3 years ago
C
Zolol [24]

The  value of this expression when =-2 and x=-1 is: 3.

<h3>Value of the expression</h3>

Given equation:

-2 and x=-1

Solving the value of the given equation

-2 and x=-1

Hence:

=-(-1)+2

=1+2

=3

Therefore the value of this expression when =-2 and x=-1 is: 3.

Learn more about Value of the expression here:

brainly.com/question/912391

brainly.com/question/625174

#SPJ1

6 0
2 years ago
PLEASE HELP AND SHOW WORK!!
Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0
3 years ago
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