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3 years ago

The probability that an archer hits a target when he shoots an arrow is 0.7. The archer shoots two

Mathematics

1 answer:

Sholpan [36]3 years ago

6 0

Answer:

The tree diagram is shown in the tree diagram is shown.

If the probability to hit is 0.7, then the probability to miss is 0.3.

P(hit, hit) = 0.7*0.7 = 0.49

P(hit, miss) = 0.7*0.3 = 0.21

P(miss, hit) = 0.3*0.7 = 0.21

P(miss, miss) = 0.3*0.3 = 0.09

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A florist arranges 4 flower arrangements in 92 minutes.

Black_prince [1.1K]

Answer:

$\boxed {\boxed {\sf 9 \ arrangements }}$

Step-by-step explanation:

Let's set up a proportion using the following setup:

$\frac{arrangements}{minutes} =\frac{arrangements}{minutes}$

We know that the florist can arrange 4 in 92 minutes.

$\frac{4 \ arrangements}{92 \ minutes} = \frac{arrangements}{minutes}$

We don't know how many the florist can arrange in 207 minutes, so we say x arrangements can be completed in 207 minutes.

$\frac{4 \ arrangements}{92 \ minutes} = \frac{ x \ arrangements}{ 207 \ minutes}$

$\frac{4}{92} =\frac{x}{207}$

Solve for x by isolating it on one side of the proportion.

x is being divided by 207. The inverse of division is multiplication. Multiply both sides of the proportion by 207.

$207*\frac{4}{92}=\frac{x}{207}*207$

$207*\frac{4}{92}=x$

$207*0.0434782609=x$

$9=x$

The florist can arrange <u>9 arrangements</u> in 207 minutes.

5 0

3 years ago

A recipe that serves 6 people calls for 1 1/2 ( mixed number) pounds of meat. You have 8 pounds of meat. How many people can you

Gnom [1K]

72 people. Multiply 8 times one and a half, and then by six.

5 0

3 years ago

Which of these limits evaluate to 0?

Vikentia [17]

<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

$\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\$

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Part II

$\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\$