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1 year ago

Simplify (9y²-x² )÷ (xy+3y²)

Mathematics

1 answer:

alexdok [17]1 year ago

6 0

Step-by-step explanation:

$\cfrac{(9y²-x² )}{ (xy+3y²)}$
$\cfrac{3 {}^{2} (y) {}^{2} - x}{3(y {})^{2} + xy }$
$3 {}^{2 - 1} y {}^{2 - 2 - 1} - x {}^{2 - 1}$
$3 y { }^{ - 1} - x$

$\cfrac{3}{y} - x$

Therefore,the answer is $\cfrac{3}{y} - x$ .

[Some of the steps I didn't show,try by yourself,to find!]

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It would be less because when you multiply something by 1/2 you are basically dividing it by 2, finding half. So when you multiply 9 8/9 by 1/2 your product would be less than 9 8/9

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2 years ago

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2 years ago

[HELP ASAP 50 POINTS] 17, 18, 19, 20

Charra [1.4K]

17) f(x) = 16/(13-x).

In order to find domain, we need to set denominator expression equal to 0 and solve for x.

And that would be excluded value of domain.

13-x =0

Adding x on both sides, we get

13-x +x = x.

13=x.

Therefore, domain is All real numbers except 13.

18).f(x) = (x-4)(x+9)/(x^2-1).

In order to find the vertical asymptote, set denominator equal to 0 and solve for x.

x^2 -1 = 0

x^2 -1^2 = 0.

Factoring out

(x-1)(x+1) =0.

x-1=0 and x+1 =0.

x=1 and x=-1.

Therefore, Vertical asymptote would be

x=1 and x=-1

19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)

We have degrees of numberator and denominator are same.

Therefore, Horizontal asymptote is the fraction of leading coefficents.

That is 7/2.

20) f(x)=(x^2+3x-2)/(x-2).

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2>1.

Degree of numerator > degree of denominator .

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3 years ago

Several students from boxerville middle stood in a circle, evenly spaced, to play a game. If the 6th student was directly across

myrzilka [38]

Answer:

There were 14 students in the circle

Step-by-step explanation:

* Lets explain how to solve the problem

- The students stood in a circle

∴ The line joining each two opposite students is the diameter

of the circle

- The 6th student was directly across from the 13th student

∴ The 6th student is opposite to the 13th student

- Lets count how many students between 6th student and

13th student

∵ 7th , 8th , 9th , 10th , 11th , 12th students between the 6th

student and 13th student

∴ There are 6 students between them

- Lets count how many students between 13th student and

6th student

∵ 14th , 1st , 2nd , 3rd , 4th , 5th students between the 13th

student and 6th student

∴ There are 6 students between them

∵ There are 6 students between 6th and 13th

∵ There are 6 students between 13th and 6th

∵ There are 2 students in 6th and 13th

∴ The number of the students = 6 + 6 + 2 = 14

∴ There were 14 students in the circle

8 0

3 years ago