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2 years ago

What is the slope of the line shown below? A. -1/4 B. 4 C. -4 D. 1/4

Mathematics

1 answer:

astra-53 [7]2 years ago

6 0

B should be the answer :)
Tell me if I’m wrong

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HELPPPPPPPPPPP WHAT IS 67+8,900+12+14+15????

Blababa [14]

Answer:

9,008

Step-by-step explanation:

67 + 12 = 79

14 + 15 = 29

79 + 29 = 108

8,900 + 108 = 9,008

plz mark me brainliest

3 0

3 years ago

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PLEASE HELP ASAP 20 POINTS!!!!!!

tankabanditka [31]

Number 1.
Subtracting Negative Is The Same As Adding.
So, It Would Be Equivalent To A
Number 2:
Subtracting From A Negative Is Making The Negative Number Larger.
So, It Would Be A
Number 3:
Positive Plus Positive Makes Larger Positive:
37 + 13 = 50.
So, 3 Is D.
Number 4:
Adding Negative Is Making Positive Numbers Smaller.
So, It Is C.
Number 5:
This Is C, Because -30 + 30 = 0 + 1 = 1

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3 years ago

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What is the volume of this prism 10mm 8mm 12mm 3mm 2mm

Solnce55 [7]

Answer:

5760 mm

Step-by-step explanation:

just multiply lol

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2 years ago

???????????????????help

Simora [160]

Answer: 10

Step-by-step explanation:

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2 years ago

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If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago