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zhannawk [14.2K]
3 years ago
12

Hi guys can l ask...... A BABY IS 3WEEKS AND 4 DAYS OLD. WHAT IS THE AGE OF THE BABY IN DAYS​

Mathematics
2 answers:
Vinvika [58]3 years ago
6 0
<h3><em>Solution</em> : - </h3>

  • 1 week = 7 days

  • 3 weeks = 3 × 7 = 21 days

  • 3 weeks and 4 days = 21 + 4 = 25 days

makkiz [27]3 years ago
3 0

Answer:

25 days old

Step-by-step explanation:

7 days = 1 week

3 x 7 = 21

21 + 4 = 25

25 days old

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Consider testing H^0: u=20 against H^a: u&lt;20 where u is the mean number of latex gloves used per week by all hospital employe
iragen [17]

Answer:

Part a: P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=46-1=45  

Since is a one sided test the p value would be:  

p_v =P(t_{(45)}  

Part b: Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.  

a. There is insufficient evidence to reject h^0

Step-by-step explanation:

Data given and notation  

\bar X=19.1 represent the sample mean

s=11.8 represent the sample standard deviation

n=46 sample size  

\mu_o =20 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is lower than 20, the system of hypothesis would be:  

Null hypothesis:\mu \geq 20  

Alternative hypothesis:\mu < 20  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{19.1-20}{\frac{11.8}{\sqrt{46}}}=-0.517    

Part a: P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=46-1=45  

Since is a one sided test the p value would be:  

p_v =P(t_{(45)}  

Part b: Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.  

a. There is insufficient evidence to reject h^0

5 0
3 years ago
5/3 raise to minus 5 into 5/3 raise to minus 11 is equal to 5/3 raise to x
Soloha48 [4]

Answer:

x = -2

Step-by-step explanation:

x^a × x^b = x^(a+b)

Similarly,

(5/3)^(-5) × (5/3)^(-11) = (5/3)^(-5-11)

= (5/3)^(-16)

-16 = 8x

x = -2

7 0
3 years ago
The midpoint of AB is M(0,2). If the
otez555 [7]

Answer:

Step-by-step explanation:

(x+2)/2 = 0

x + 2 = 0

x = -2

(y - 3)/2 = 2

y - 3 = 4

y = 7

(-2, 7)

8 0
3 years ago
A1=-3 and an= an-1+7
lubasha [3.4K]

Step-by-step explanation:

The answer is an = 7n - 10.

7 0
3 years ago
Identify the lateral area and surface area of a regular square pyramid with base edge length 11 cm and slant height 15 cm, round
Ann [662]

The surface area of the square pyramid is: 451 cm²

The lateral surface area of the square pyramid = 330 cm²

<h3>What is the Lateral Surface Area and Surface Area of a Square Pyramid?</h3>

Surface area = a² + 2al, where a is the base edge and l is the slant height.

Lateral Surface Area =  2al.

Given the following:

  • a = 11 cm
  • l = 15 cm

Surface area = a² + 2al = 11² + 2(11)(15)

Surface area = 451 cm²

Lateral Surface Area =  2al = 2(11)(15)

Lateral Surface Area = 330 cm²

Learn more about square pyramid on:

brainly.com/question/3688277

3 0
2 years ago
Read 2 more answers
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