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blondinia [14]
4 years ago
14

Hey its really easy but help me pls

Mathematics
2 answers:
ddd [48]4 years ago
6 0

D is correct.

Hope this helps. :)

You divide the top number to the bottom number. So it would be top number divided by bottom number.

natita [175]4 years ago
5 0

Answer:

D) 26/48

Step-by-step explanation:

/ = division sign

26/48 also means 26 divided by 48.

Simple math.

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A polygon with 12 sides is called a/an <br> a. dodecagon. <br> b. pentagon. <br> c. undecagon.
Pepsi [2]
The answer is A. dodecagon.
5 0
3 years ago
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Water Street intersects 25th Street and 28th Street at right angles. Highway 47 is parallel to 28th Street. How are 25th Street
mezya [45]

Answer:

  • 25th Street is parallel with Highway 47

Step-by-step explanation:

Water Street intersects 25th Street and 28th Street at right angles.

  • <u>Outcome</u> ⇒ 25th Street and 28th Street are parallel

Highway 47 is parallel to 28th Street.

  • <u>Outcome</u> ⇒ 25th Street is parallel with Highway 47
5 0
3 years ago
Read 2 more answers
2x(x -2)+16=2(2×+9) solve equation
nata0808 [166]

Answer:

x

=

1

+

√

11

,

1

−

√

11

Decimal Form:

x

=

4.31662479

…

,

−

2.31662479

…

Step-by-step explanation:

4 0
4 years ago
Janet has three coins.
tatyana61 [14]

Answer:

Janet has coins worth 252.5, 101, and 50.5.

Step-by-step explanation:

Let us call the three coins a,b, and c.

The first coin a is 5 times another coin<em> (let's say </em>b); therefore,

a = 5b,

and the third coin is 2 times the value of another coin<em> (it's coin </em>b<em>):</em>

<em />c =2b<em>.</em>

The total worth of all coins is 404; therefore,

a+b+c =404

or

5b+b+2b =404

8b =404

\boxed{b = 50.5}

with the value of b in hand, we find a and c:

a = 5b = 5(50.5)

\boxed{a = 252.5}

and for c:

c = 2 b = 2 (50.5)

\boxed{c = 101}

Thus, Janet has 3 coins worth 252.5, 101, and 50.5.

8 0
4 years ago
The following data show the average retirement ages for a random sample of workers in the United States and a random sample of w
SSSSS [86.1K]

Answer:

t \approx 2.639

Step-by-step explanation:

Given

\begin{array}{ccc}{} & {USA\ 1} & {Japan\ 2} & {\bar x} & {64.6} & {67.5} &{n} & {30} & {30} & {\sigma} & {4.0} & {4.5} \ \end{array}

See attachment for data

Required

Determine the test statistic

The test statistic is calculated using:

t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}}

So, we have:

t = \frac{64.6 - 67.5}{\sqrt{\frac{4.0^2}{30} + \frac{4.5^2}{30}}}

t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00}{30} + \frac{20.25}{30}}}

t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00+20.25}{30}}}

t = \frac{64.6 - 67.5}{\sqrt{\frac{36.25}{30}}}

t = \frac{-2.9}{\sqrt{1.2083}}

t = \frac{-2.9}{1.099}

t \approx -2.639

The absolute value is:

t \approx 2.639

3 0
3 years ago
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