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3 years ago

For what value(s) of x is the fraction 5x-10/x^2-25 undefined?

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

Answer:

+5 or -5.

Step-by-step explanation:

Given equation,

5x-10/x^2-25

When you divide something with zero, it becomes undefined. So, to be undefined, x will have to be that value which makes the divisor zero.

Now, x^2-25= 0

Or, x^2= 25

Or, x= +5,-5.

So, for the value +5 and -5, the divisor becomes zero and makes the whole equation undefined.

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8.45x10^-2 in standard form?

grin007 [14]

The 10^-2 means move decimal to the left 2 places
0.845 is 1 place
0.0845 is 2

so the standard is 0.0845

4 0

3 years ago

Read 2 more answers

Is 9 + 3 + 6x the simplify expression of 9 - (3 - 6x)?

Vinil7 [7]

E. he did not multiply 3 by -1 correctly

The simplify expression is 9 - 3 + 6x = 6 + 6x

4 0

3 years ago

A school chorus has 90 sixth-grade students and 75 seventh-grade students. The music director wants to make groups of performers

Vera_Pavlovna [14]

Answer:

a) 15 is the largest number of groups that can be made.

b) There would 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

Number of sixth-grade students = 90

Number of seventh-grade students = 75

a) What is the largest number of groups that could be formed?

Since the music director wants to make groups with the same combination of sixth and seventh grade students in each group,

The greatest common factor (GCF) of the number of sixth and seventh grade students would give us the required combination.

Factor of 90 = 2*45 = 2*3*15 = 2*3*3*5

Factor of 75 = 3*25 = 3*5*5

The greatest common factors are 3 and 5

GCF = 3*5 = 15

Therefore, 15 is the largest number of groups that can be made.

b. If that many groups are formed, how many students of each grade level would be in each group?

Sixth grade = 90/15 = 6

Seventh grade = 75/15 = 5

Therefore, there would 6 sixth grade students and 5 seventh grade students in each group.

7 0

3 years ago

Halim makes a profit of 120% on his cost price by selling a pair of shoes of $45. i) Find the cost pricer of the pair of shoes i

Rus_ich [418]

Answer:

a. $20.45

b. $24.55

c. $4.55

Step-by-step explanation:

In this question, we are asked to calculate the cost price and profit or loss selling a pair of shoes.

we proceed as follows

Firstly, we want to find the cost price given the selling price and the mark up percentage.

mathematically;

profit =( selling price - cost price)/cost price * 100%

here our profit is 120% with the cost price being $45. we plug these values

120 = 45-cp/cp * 100%

120cp = 100(45-cp)

120cp = 4500 -100cp

220cp = 4500

cp = 4500/220 = $20.45

His profit is selling price - cost price = 45 - 20.45 = $24.55

His profit selling same shoe for $25 is 25-20.45 = $4.55

4 0

3 years ago

Read 2 more answers

9. Given the point (6,-8) values of the six trig function.

lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10

$\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}$

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

$\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}$

3 0

3 years ago