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IgorC [24]
3 years ago
5

A system of linear equations with fewer equations than unknowns is sometimes called an underdetermined system. Can such a system

have a unique​ solution? Explain. Choose the correct answer below. A. ​No, it cannot have a unique solution. Because there are more variables than​ equations, there must be at least one free variable. If the linear system is consistent and there is at least one free​ variable, the solution set contains infinitely many solutions. If the linear system is​ inconsistent, there is no solution.
Mathematics
1 answer:
elena55 [62]3 years ago
3 0

Answer:

No, it cannot have a unique solution. Because there are more variables than​ equations, there must be at least one free variable. If the linear system is consistent and there is at least one free​ variable, the solution set contains infinitely many solutions. If the linear system is​ inconsistent, there is no solution.

Step-by-step explanation:

the questionnaire options are incomplete, however the given option is correct

We mark this option as correct because in a linear system of equations there can be more than one solution, since the components of the equations, that is, the variables are multiple, leaving free variables which generates more alternative solutions, however when there is no consistency there will be no solution

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Answer: If you mean five instead of time, then the answer would be 82.5

Step-by-step explanation:

15 × 5.5 = 82.5

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Solve 7.8e^((x/3)ln(5))=14. What are the exact and approximate solutions?
Dimas [21]

\bold{\text{Answer}:\quad x=3\bigg(\dfrac{ln\frac{14}{7.8}}{ln(5)}\bigg)=1.09}

<u>Step-by-step explanation:</u>

7.8e^{\frac{x}{3}\cdot ln(5)}=14\\\\\\e^{\frac{x}{3}\cdot ln(5)}=\dfrac{14}{7.8}\\\\\\ln\bigg(e^{\frac{x}{3}\cdot ln(5)}\bigg)=ln\bigg(\dfrac{14}{7.8}\bigg)\\\\\\\frac{x}{3}}\cdot ln(5)=ln\bigg(\dfrac{14}{7.8}\bigg)\\\\\\\large\boxed{x=3\bigg(\dfrac{ln\frac{14}{7.8}}{ln(5)}\bigg)}\\

x ≈ 1.09

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3 years ago
What’s a other word for adjacent I need help
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Pam needs 3 1/2 cups of sugar to make 50 cupcakes. A 5- pound bag of sugar coats $3.69. There are about 2 cups of sugar in a pou
Lorico [155]

Answer:

The answer to your question is $1.29

Step-by-step explanation:

Data

Total amount of cupcakes = 50

Total amount of sugar = 3 1/2 cups = 3.5 cups

Cost of 5-pound bag = $3.69

2 cups = 1 pound

Total cost = ?

Process

1.- Calculate the amount of pounds needed

                  2 cups ------------------ 1 pound

                  3.5 cups ---------------  x

                  x = (3.5 x 1) / 2

                  x = 3.5 / 2

                  x = 1.75 pounds

2.- Calculate the price of 1.75 pounds

                  5 pounds -------------- $3.69

                  1.75 pounds ----------    x

                  x = (1.75 x 3.69)/5

                  x = 6.46/5

                 x = $1.29

3.- Conclusion

The cost of sugar to prepare 50 cupcakes is $1.29

3 0
3 years ago
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