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ExtremeBDS [4]
3 years ago
15

How do you solve -h/3 - 4 = 13

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0
Answer is -h = -51 (download photomath)

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What is m<br> A.55°<br> B.58°<br> C.122°<br> D.125°
Andreyy89

Answer: k = 55 degrees

Step-by-step explanation:

to find J, subtract 122 from 180, you get 58. The total number of degrees is 180. Since L is given as 67, and 67+58=125. Simply subtract 125 from 180 which is 55 degrees

5 0
3 years ago
What is the answer to this question it doesn't state the answer so can you please tell me the answer
DiKsa [7]
I DONT KNOW JUST STRAT WITH THE BEGGINIG OF THE SENTENCE 

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3 years ago
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<img src="https://tex.z-dn.net/?f=54x2y%20-%2012x2y2" id="TexFormula1" title="54x2y - 12x2y2" alt="54x2y - 12x2y2" align="absmid
Free_Kalibri [48]

Answer:

6x²y(9 - 2y)

Step-by-step explanation:

Step 1: Factor out GCF

6(9x²y - 2x²y²)

Step 2: Factor out <em>x²</em>

6x²(9y - 2y²)

Step 3: Factor out <em>y</em>

6x²y(9 - 2y)

And we have our factored answer.

7 0
3 years ago
Read 2 more answers
Write in exponential notation: 301=​
dalvyx [7]

Answer:

3.01 * 10^2

Step-by-step explanation:

=)

Hope this helps!

4 0
2 years ago
PLZ HELP DONT UNDERSTAND!!!
victus00 [196]
\bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad &#10;\begin{cases}&#10;b=base\\&#10;h=\textit{height or altitude}&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;\textit{area of a trapezoid}\\\\&#10;A=\cfrac{h}{2}(a+b)\qquad &#10;\begin{cases}&#10;a=\textit{base, or one of the parallel sides}\\&#10;b=\textit{base, or the other parallel side}\\&#10;h=\textit{height, the distance between both}\\&#10;\qquad \textit{parallel sides}&#10;\end{cases}
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3 years ago
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