-15x - 3y = 3
-15x - 3(5x-1) = 3 [input y]
-15x - 15x - 3 = 3 [distribute 3 over 5x and -1]
-30x - 3 = 3 [combine like terms]
-30x = 6 [add 3 to eliminate the negative]
x =
[divide by -30 to get x alone]
x =
[reduce the fraction]
Hopefully this is helpful enough to get you to your answer
40x+8x^2=0 can be solved for x (there are two solutions):
Divide all 3 terms by the greatest common multiple (which is 8x):
40x+8x^2=0
------------- -----
8x 8x
5 + x = 0 produces the root x = - 5.
Setting 8x = 0 and solving for x produces the root x = 0.
Be certain to check these results. substitute x = -5 into 40x+8x^2=0. Is the resulting equation true or false? Next, subs. x=-5 into 40x+8x^2=0. Is the resulting equation true or false?
ok thanks for letting me know you need help
Answer:
Rs 175
Step-by-step explanation:
Suppose the cost is x and at Rs150 the loss is 150-x (this should be a negative number).
At Rs200, the profit is 200-x.
So we have an equation: minus 150 minus x is equal to 200 minus x.
To solve the equation, the cost price X is Rs175.
Answer:
D. RWS and SWT
Step-by-step explanation:
Adjacent angles have a common side and a common vertex but they don't overlaps each other
The two angles that has these requirements are :
RWS and SWT
