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3 years ago

Solve log (x + 1) = –x2 + 10 by graphing

Mathematics

2 answers:

irga5000 [103]3 years ago

5 0

Answers on edguinity are y1 = –x2 + 10 and y2 = log (x + 1).

Anit [1.1K]3 years ago

3 0

Your answer would be x = 3.0645

CHECK
log (3.0645 + 1) ?=? -(3.0645)2 + 10
log 4.0645 ?=? -9.3912 + 10
0.609 ?=? 0.609

Hope this helps!

So in short your answer is x = 3.0645

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the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years

Yuliya22 [10]

Answer: 125 g

<u>Step-by-step explanation:</u>

$A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k$

$\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125$

8 0

3 years ago

18=k+12 HELPPP WHATS K

Nana76 [90]

Answer:

k=6

Step-by-step explanation:

18=k+12

you need to isolate k so you subtract 12 from both side

6=k

7 0

3 years ago

Read 2 more answers

A student solved the following problem and made an error:

liubo4ka [24]

All the steps were correct except the final statement. The mistake was in Line 6.

Line 6 triangle ABC is congruent to triangle EFD by SAS.

<span>This does not follow. The SAS postulate states that if two sides and the included angle of one triangle is congruent to two sides and the included angle of another triangle. The student only proved that one side of the triangle (AC) is congruent to the side of another triangle (EF) .</span>

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3 years ago

\frac{3}{4} \times 2 =

suter [353]

To multiply two fractions, you simply multiply numerators and denominators together.

2 can be read as the fraction 2/1

So, the multiplication is

$\dfrac{3}{4} \times \dfrac{2}{1} = \dfrac{3\times 2}{4 \times 1} = \dfrac{6}{4} = \dfrac{3}{2}$

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3 years ago

A can in the shape of a cylinder has a diameter of 10 cm and a height of 6 cm. how much wrapping paper is needed to cover the cy

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

To determine the amount of wrapping paper needed to cover the can, we would determine the total surface area of the cylindrical can. The formula for determining the total surface area of a cylinder is expressed as

Total surface area = 2πr² + 2πrh

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

From the information given,

Diameter = 10 cm

Radius = diameter/2 = 10/2

Radius = 5 cm

Height = 6 cm

Therefore,

Total surface area = (2 × 3.14 × 5²) + (2 × 3.14 × 5 × 6)

= 157 + 188.4 = 345.4 cm²

345 cm² of wrapping paper is needed to cover the cylinder.

2) Volume of cylinder = πr²h

Volume of cone = 1/3πr²h

3 × Volume of cone = πr²h

The volume of the cylinder is 3 times greater than the volume of the cone. Therefore, the volume of the cone is 1/3 times lesser than the volume if the cylinder.

5 0

3 years ago