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Naya [18.7K]
3 years ago
14

18=k+12 HELPPP WHATS K

Mathematics
2 answers:
Nana76 [90]3 years ago
7 0

Answer:

k=6

Step-by-step explanation:

18=k+12

you need to isolate k so you subtract 12 from both side

6=k

Elena L [17]3 years ago
6 0
<h3>Hm ok, so the answer here would be <u>k=6</u>, and heres why:</h3>

So to solve these types of problems you must first separate the variables from the rest of the equation. Normally it is the Y variable if there is multiple variables like X and Y.

In this case, K is basically our Y. This is what the the first step for any problem like this:

18=k+12\\\\-12+18=k+12-12

The reason for this is to get the like types of variables, such as numbers and letters, on the same side.

<u>NOW IF </u>you come across a different question that has something like this:

3k

I'm using K and the same equation basically to keep things simple, but it's also true if there is a number next to a Y.... and sometimes X.

IF you see something like this, the next step to solve is this:

6=3k\\\\\frac{6=3k}{3} \\2=k

Anything after the first NOW IF is irrelevant to this question, but please keep it in mind just in case, ok? It may save you some work later.

<h3>Now If you like this answer and you would like to see more like it, Please make sure Like, Comment, and Rate this answer! Also, make sure to send me a Friend request. I'm always up for a Challenge!</h3><h2>Thanks!</h2>

ps. could you please mark me Brainlyest? I kinda need it to maintain and reach my next rank... thx

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o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
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Answer?

What do you need help with? :)

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The answer is B, -12.

Please give me brainliest.

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