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lisov135 [29]
3 years ago
5

How do you solve

lt="9^{2x-1}=9^{3x-2}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
4 0

Since  x  is on the right side of the equation, switch the sides so it is on the left side of the equation.

2 ( 5 − 2 x ) − ( 1 − 5 x ) 9 − 3 x

Simplify the left side.

x + 9 = 9 − 3 x

Move all terms containing  x  to the left side of the equation.

4 x + 9 = 9

Move all terms not containing  x  to the right side of the equation.

4 x = 0

Divide each term by  4 and simplify.

x = 0

ra1l [238]3 years ago
4 0

They have the same base, so just look at the powers.   2x - 1 = 3x - 2   Isolate the x. Subtract 3x from both sides and add 1 to both sides   2x (-3x) - 1 (+1) = 3x (-3x) -2 (+1)   2x - 3x = -2 + 1   Simplify -x = -1   Isolate the x. Divide -1 from both sides (-x)/-1 = (-1)/-1   x = 1   1 is your answer for x    Hope this helps

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