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Viefleur [7K]
3 years ago
11

The Byrds. You have 16 new CDs to put on your empty five-shelf CD rack. Can you place the CDs so that each shelf contains three

or fewer CDs? Can you arrange them so that each shelf contains exactly three?
Mathematics
2 answers:
Nutka1998 [239]3 years ago
8 0

Answer:

  1. No we cannot place the CDs in such a manner that each shelf contains three or fewer CDs
  2. No We cannot arrange them so that each shelf contains exactly three

Step-by-step explanation:

In this question we have given

Total number of CDs to put on empty shelf CD rack=16

Number or shelf in a CD rack=5

part 1:

Can you place the CDs so that each shelf contains three or fewer CDs

Answer:

No we cannot place the CDs in such a manner that each shelf contains three or fewer CDs because there are 16 CDs which we have to keep in 5 shelf so each shelf will contains at least 3 CDs and one shelf will contains 4 CDs(Because=\frac{16}{5}= 3.2). If we place 3 or less CDs in each shelf than 15 or less than 15 CDs can be kept in all the 5 shelf

Part 2

Can you arrange them so that each shelf contains exactly three?

Answer :

No We cannot arrange them so that each shelf contains exactly three if we do so than 1 CD will be remain outside the shelf as 5\times 3=15

bulgar [2K]3 years ago
5 0
If each shelf is to contain exactly 3 new CDs and there are only 5 shelves, only 15 can be placed in the rack. So, the answer to the second question is no. The same goes for the first question as placing 3 or fewer CDs to the shelves will make the rack insufficient for the CDs. 
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eimsori [14]

Answer:

Sasha stopped working at 12:10 PM

Step-by-step Explanation

8:30 + 3 hours and 40 minutes = 12:10 PM

Mark as brainliest if it's right!

3 0
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I need help on this problem
zhannawk [14.2K]
We know the length and width. We're just  trying to find all of the area in between. To find area, we do length*width. Length is 11.5 and the width is 10.75. 11.5*10.75=123.625 ft^2
3 0
3 years ago
Questions are in the screenshot.
White raven [17]

For question 4, x = 18 units,

For question 5, x = 8.333 units.

Step-by-step explanation:

Step 1:

Since the given polygons are similar to each other, all the ratios of one polygon to the other will remain equal for all the values of the two similar polygons.

We take the ratio of the same sides of both polygons i.e. the ratio of the lengths or the ratio of the widths.

Step 2:

For question 4, the first rectangle has a length of 9 units while the width is 3 units.

For the second rectangle, the length is x as x is greater than the width in the first rectangle. The width is 6 units.

The ratio of the first rectangle to the second is;

\frac{3}{6} : \frac{9}{x} , x = (9)(\frac{6}{3} ) = 18. So x = 18 units.

Step 3:

The shapes in question 5 are made of a square and a triangle.

For the first shape, the side length is 6 units while the side of the triangle is 10 units.

For the second shape, the side length is 5 units while the side of the triangle is x units.

The ratio of the first shape to the second is;

\frac{6}{5} : \frac{10}{x} , x = (10)(\frac{5}{6} ) = 8.333. So x = 8.333 units.

6 0
3 years ago
Find the
Mazyrski [523]

Answer:

54 cm

Step-by-step explanation:

The area (A) of an equilateral triangle is

A = \frac{s^2\sqrt{3} }{4}  ( s is the side length ) then

\frac{s^2\sqrt{3} }{4} = 81\sqrt{3} ( multiply both sides by 4 to clear the fraction )

s²\sqrt{3} = 324\sqrt{3} ( divide both sides by \sqrt{3} )

s² = 324 ( take the square root of both sides )

s = \sqrt{324} = 18

Thus

perimeter = 3 × 18 = 54 cm

3 0
3 years ago
The average of 5 quiz grades is 10. When the lowest grade is dropped and the new average is calculated, it turns out to be 11. W
V125BC [204]

Answer:

The score of the dropped grade is 6

Step-by-step explanation:

To find the average of a set of numbers you need to add all the numbers and divide by how many numbers there are. The problem wants you to solve it in reverse. Let put this into an algebraic equation with a, b, c, d, and e being the variables of the test scores

(a+b+c+d+e)/5=10

Then we can multiply both sides by 5 and get

a+b+c+d+e=50

Lets assume that c is the lowest test score. To calculate the average of that we get

a+b+d+e/4=11

Doing the same thing, we know that a+b+d+e=44

Now compare the two:

a+b+c+d+e=50

a+b+d+e=44

We can now know that c=50-44=6

So, 6 is the score of the dropped quiz. Hope that helped!

4 0
2 years ago
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