The answer you want is -10
Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
There is a 1/2 chance that he will get at least one of the two features.
There are 3 x 4 = 12 possibilities. There are all 4 colors of each 3 sizes.
All 4 of the medium trucks have one of the features.
For the other 2 sizes, only the red truck will have one of the features.
There are 4 + 2 = 6 possibilities out of 12 for a chance of 6/12 or 1/2.
Answer:
answer is 2
Step-by-step explanation:
if you create an equation: (s+4)x2 = boris s-1x12 = opa
only one that only works out is 2