We can make use of the general formula for the geometric series to generate the function representing the average annual salary.
an = a0(r)^(n-1)

Or
f(x) = a0(r)^(x - 1)

Plugging in the given values for the year 2005 and 2006 to ge the value of r.
82000 = 70000 (r)^(1-1)
r = 1.1714

Therefore, the function is:
f(x) = 70,000 (1.1714)^(x-1)

3 0

3 years ago

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If the circumference is 3/2 pi what is the area

11111nata11111 [884]

Here is your answer

$\frac{9}{16} \pi \: {units}^{2}$

REASON:

Circumference(C)= 2πr

, where r is radius

Given

C= (3/2) π

So,

$2\pi \: r = \frac{3}{2}\pi$

$r = \frac{\frac{3}{2}\pi}{2\pi}$

$r = \frac{3}{4}$

Now,

$area = \pi {r}^{2}$

$= \pi \times { (\frac{3}{4}) }^{2}$

$= \frac{9}{16}\pi \: {unit}^{2}$

HOPE IT IS USEFUL

8 0

4 years ago

I can't get to get this right can you please help me

monitta

Answer:

$(-7,4]\text{ or }\{x|-7$

Step-by-step explanation:

The domain is the span of x-values covered by the function.

From the graph, we can see that the graph covers all the x-values from x=-7 to x=4.

However, note that closed and open circles. There is an open circle at x=-7, which means that the domain excludes x=-7. However, the circle at x=4 is closed, meaning it is included in the domain.

Therefore, the domain is, in interval notation:

$(-7,4]$