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4 years ago

Pls help with these asap

Mathematics

1 answer:

____ [38]4 years ago

3 0

I think number 5 is A, the picture is kind of blurry.
3²×4²×3^4 = 3^6×4²

Number 6 is B.
In 5x+2
The +2 means two more and the 5x is five times a number,
therefore, it would be two more than five times a number

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Triangle GHJ with vertices G(-2, 4), H(3, 6), and J(3, -2) is dilated by a factor of 1/3 centered at the origin. What are the co

Grace [21]

Answer:

The coordinates of G' are $G'(x,y) = \left(-\frac{2}{3}, \frac{4}{3} \right)$ .

Step-by-step explanation:

From Linear Algebra, we define the dilation of point G by the following expression:

$G'(x,y) = O(x,y) + k\cdot [G(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation, dimensionless.

$k$ - Scale factor, dimensionless.

$G(x,y)$ - Coordinates of point G, dimensionless.

$G'(x,y)$ - Coordinates of point G', dimensionless.

If we know that $O(x,y) = (0,0)$ , $k = \frac{1}{3}$ , $G(x,y) = (-2,4)$ , then the point G' is:

$G'(x,y) = (0,0) + \frac{1}{3}\cdot [(-2,4)-(0,0)]$

$G'(x,y) = \left(-\frac{2}{3}, \frac{4}{3} \right)$

The coordinates of G' are $G'(x,y) = \left(-\frac{2}{3}, \frac{4}{3} \right)$ .

7 0

3 years ago

Can someone please help out with this. I know I did the problem incorrectly.

Sloan [31]

Answer:

Correct answer: C. -20

Step-by-step explanation:

If (x-3) is a polynomial factor it means that the polynomial value at point 3 is zero.

H(3) = 3 · 3³ - 2 · 3² + 3k - 3 = 0 ⇒ 81 - 18 + 3k - 3 = 0 ⇒ 3k + 60 = 0

3k = - 60 ⇒ k = - 60/ 3 = - 20

k = - 20

God is with you!!!

4 0

4 years ago

A person invests 8000 dollars in a bank. The bank pays 5% interest compounded monthly. To the nearest tenth of a year, how long

REY [17]

Answer:

3 years

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help!!

Vikentia [17]

421 because 9% of 290 is 26.1 so you multiply that by 5 and add 290 and you get 420.5 so you get 421 rounded to the nearest whole number

4 0

3 years ago

I need to know order pairs for this equation

kompoz [17]

Hi, you haven't provided the equation that you need order pairs for.

Therefore, I'll just explain how to find order pairs in general and you can apply the same method to the the equation you have

Answer with explanation:

Order pairs of any equation are (x,y) values that satisfy this equation

To get them, the simplest way is to assume a value for x, use this value to substitute in the equation you have and then solve for the corresponding y

Example:

Consider the equation: x + 2y = 8

at x = 0: 0 + 2y = 8 ............> 2y = 8 ..........> y = 4 ............> order pair is (0,4)

at x = 2: 2 + 2y = 8 ............> 2y = 6 ..........> y = 3 ............> order pair is (2,3)

at x = 4: 4 + 2y = 8 ............> 2y = 4 ..........> y = 2 ............> order pair is (4,2)

Now, we can say that (0,4), (2,3) and (4,2) are order pairs that satisfy the given equation

For your equation:

1- Assume value of x

2- Substitute with that value in the equation

3- Solve the equation for the corresponding y

4- The order par pair would be:

(assumed x value , corresponding calculated y value)

Hope this helps :)

3 0

3 years ago