( brainliest )<br><br> What is the area of this figure?

Find the sum of the measures of the interior angles of a polygon with 41 sides

Zolol [24]

Answer:

the formula is (n-2)180 degrees

so its 7020

8 0

2 years ago

A mix of factoring by grouping. Factor the exressions. 17ax+17a-x-1 Please explain/show steps on how to do this!

mario62 [17]

Answer:

$(x+1)(17a-1)$

Step-by-step explanation:

We are given that

$17ax+17a-x-1$

We have to factorize the given expression.

Pair up the terms

$(17ax+17a)+(-x-1)$

Now, taking common factor

$17a(x+1)-1(x+1)$

Taking common (x+1)

$(x+1)(17a-1)$

Now, we get

$(x+1)(17a-1)$

This is required factors of given expression.

4 0

3 years ago

1.) You (or your parents) purchase a new car for $19,725.00 plus 4.75% sales tax. The down payment is $2,175.00 and you (or your

Helga [31]

Answer:

$936.94

Step-by-step explanation:

Remember, that because you paid $2,175 up front (down payment), you can borrow $2,175 less from the bank to purchase the car. So first step: Take new car price of $19,725.00 and multiply it by the sales tax percentage ($19,725 * 0.0475) to get $936.94 of tax.

4 0

3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: