Question

How to solve for a and b

Answer 1

$\bf \begin{cases} 3=a\cdot b^0\\ 75=a\cdot b^2 \end{cases}\qquad b^0=1\implies \begin{cases} 3=a\cdot 1\implies 3=a\\ ----------\\ 75=a\cdot b^2\implies 75=3\cdot b^2\\\\ \frac{75}{3}=b^2\implies 25=b^2\\\\ \pm \sqrt{25}=b\implies \pm 5 = b \end{cases}$

recall, anything raised to the 0, zero, power, is 1, with the sole exception of 0