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3 years ago

Compose a poem related to saturated and unsaturared solution

Chemistry

1 answer:

Setler [38]3 years ago

6 0

Answer:

The supersaturated solution

it is a solution usually very sugary

excess solute

the supersaturated solution is a solution

where there is solute and solvent, there is always interaction

Explanation:

The supersaturated solutions are solutions where the solute is in excess, the solute is in constant interaction with the solvent and being in excess it precipitates to the bottom of the solution.

A supersaturated solution has a very high osmolarity.

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4. What are the two ways that you can recognize a numeric place changes (1s vs. 10s vs. 100s) on a micropipettor?

Serjik [45]

it's 100,0002 pn a micropipettor

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2 years ago

What ecosystem is being described in the passage?

Ad libitum [116K]

Answer:were is the passage

Explanation:

We’re the pasagee

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3 years ago

Sodium chloride, NaCl forms in this reaction between sodium and chlorine. 2Na(s) + Cl2(g) → 2NaCl(s) How many moles of NaCl resu

choli [55]

Answer: 7.8 moles of NaCl result from the complete reaction of 3.9 mol of $Cl_2$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}$

$\text{Moles of} Cl_2=3.9mol$

$2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)$

As $Na$ is the excess reagent, $Cl_2$ is the limiting reagent as it limits the formation of product.

According to stoichiometry :

1 mole of $Cl_2$ gives = 2 moles of $NaCl$

Thus 3.9 moles of $Cl_2$ will give= $\frac{2}1}\times 3.9=7.8moles$ of $NaCl$

7.8 moles of NaCl result from the complete reaction of 3.9 mol of $Cl_2$

5 0

3 years ago

A certain first-order reaction (A→productsA→products) has a rate constant of 9.90×10−3 s−1s−1 at 45 ∘C∘C. How many minutes does

coldgirl [10]

Answer:

4.66667 minutes

Explanation:

Rate constant, k = 9.90×10−3 s−1

Time = ?

Initial concentration, [A]o = 100

Final concentration, [A] = 6.25

The integral rate law for first order reactions is given as;

ln[A] = ln[A]o − kt

kt = ln[A]o - ln[A]

t = ( ln[A]o - ln[A]) / k

t = [ln(100) - ln(6.25)] / 9.90×10−3

t = 2.77 / 9.90×10−3

t = 0.28006 ×103

t = 280 seconds

t = 4.66667 minutes (Upon conversion by dividing by 60)

4 0

3 years ago

Write an expression that can be used to check the quotient of 646÷3

iVinArrow [24]

Answer:

215.33

Explanation:

A mathematical expression is an equation that connect one or more variables with constants.

The Quotient is the result of carrying out the division operation.let "y" be the quotient of dividing 646 by 3

therefore 646÷3 =y

$\frac{646}{3}=y\\ 3y=646\\$

$y=\frac{646}{3}\\ y=215.33$

5 0

3 years ago