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3 years ago

Mark got 14 problems wrong in his test. His score was 72% correct. How many problems were on the test?

Mathematics

1 answer:

dedylja [7]3 years ago

4 0

Answer:

50 Questions

Step-by-step explanation:

14 out of 100 wrong gets 72% correct is equal to 28%

Compare the Score earned and a perfect score.

14/x = 28/100

1400=28x

50=x

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Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

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3 years ago

What is the initial value of the function represented by this graph?

Tasya [4]

Omg this is y’all work

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3 years ago

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Please help, I need this quickly. Fairly easy, help pleasee

ahrayia [7]

-4x-3y-9=0
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12x-y-17=0
|| m1= -12/-1=12
_|_ m2 = -1/12

x-y=0
|| m1= -1/-1=1
_|_ m2= -1

8x - 3y - 2=0
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4 years ago

Solve the variable x. 12yx = 5z

romanna [79]

Answer:

$\boxed{\bold{x \ = \ \frac{5z}{12y} }}$

Explanation:

Solve For X: 12yx = 5z

[ Divide Both Sides By 12y ]

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seropon [69]

Answer:

its sim iler

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