Answer:
The motherboard must be configured to accept a particular type of memory.
Explanation:
The motherboard must be configured to accept a particular type of memory, especially when dealing with multi-channel memory. On motherboard, different modes can be configured to run simultaneously . For motherboard to take advantage of the triple memory channels on the board. You can also check the manual that came with the motherboard to know how to configure it.
Answer:
Multi herramientas
Explanation:
Un kit tecnologico debe contener todas las herramientas necesarias para el trabajo que lo necesites, por ejemplo destornillador magnetico con varias puntas, herramientas para desmontar y por supuesto tener buena claridad para trabajar y alcohol isoprofilico de al menos 90+ para limpiar electronicos.
Answer:
The answer to the given question can be given as:
The value of *iptr is 7. and the value of iptr is dynamic.
Explanation:
In the c++ code, it is defined that x is an integer variable that assigns a value which is 7. Then we define a pointer variable that is *iptr. This variable holds an address of the x variable. When we print the value of the iptr variable. if we use the expression *iptr to print value of the pointer variable by cout that is used in c++ for pint values. so the value of the iptr is 7. If we use the expression iptr sent to cout so we show the address of the variable x. In the pointer, it manages the addresses of dynamically allocated so the address of the variable is changed on execution time.
Answer:
a) the Statement is Invalid
b) the Statement is Invalid
Explanation:
a)
lets Consider, s: student of my class
A(x): Getting an A
Let b: john
I have a student in my class who is getting ab A: Зs, A(s)
John need not be the student i.e b ≠ s could be true
Hence ¬A(b) could be true and the given statement is invalid
b)
Lets Consider G: girl scout
C: selling 50 boxes of cookies
P: getting prize
s: Suzy
Now every girl scout who sells at least 50 boxes of cookies will get a prize: ∀x ∈ G, C(x) -> P(x)
Suzy, a girl scout, got a prize: s ∈ G, P(s)
since P(s) is true, C(s) need not be true
Main Reason: false → true is also true
Therefore the Statement is Invalid
