A circle with its dimensions in inches (in), is shown what is the area in square inches of half the circle

1 answer:

8 0

If you could tell us the dimensions of the circle we would gladly help you with your question. However it is almost impossible to find the area of half of the circle without knowing the dimensions.

Hope this helps!

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A textbook weighs 2.5 pounds. How many kilograms does the textbook weigh? Round your answer to the nearest tenth of a pound. 1 k

Alenkasestr [34]

The solution to the problem is as follows:

Given: 2.5 lb

Asked: 2.5 lb -----> kg

Answer:

2.5 lb * ( 1 kg/2.2 lb) = 1.1 kg

Therefore, the weight of the book in kg is 1.1 kg.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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3 years ago

George collects 25 baseball cards each month. How many cards will he have at the end of one year? Complete the equation to help

kaheart [24]

25(cards per month) x12(months in one year) =300 cards at the end of one whole year

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3 years ago

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Cynthia Besch wants to buy a rug for a room that is 19 ft wide and 32 ft long. She wants to leave a uniform strip of floor aroun

Rainbow [258]

Answer:

The rug should be 15 ft wide and 28 ft long.

Step-by-step explanation:

I have attached a figure that represents the situation.

The the rug is $l$ by $h$ , the width of the strip of floor is $w$ .

We are told that Cynthia can only afford 420 square feet of carpeting; therefore, it must be that

$l*h=420$ <em>(this says the area of the rug must be 420 square feet)</em>

From the figure we see that

$l= 32-2w$

$h=19-2w$

Therefore,

$l*h=420\\\\(32-2w)(19-2w)=420$

We expand this equation and get:

$4w^2-102w+608=420\\\\4w^2-102w+188=0$

using the quadratic equation we get two solutions:

$w=2\\w=23.5$

since the second solution, namely $w=23.5$ , is larger than one of the dimensions of the room (is greater than 19 ft) it cannot be the width of the strip; therefore, we take $w=2$ to be our solution.