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Gwar [14]
3 years ago
13

A rectangular box has length x and width 3. The volume of the box is given by y = 3x(8 – x). The greatest x-intercept of the gra

ph of this polynomial equals which of the following?
Choose all that apply.
The maximum possible width.
The maximum possible length.
The minimum possible height.
The maximum possible height.
The maximum possible volume.
 
(Can you also please tell me how you did it? I'm trying to learn. You don't have to though)

Mathematics
1 answer:
CaHeK987 [17]3 years ago
7 0

Consider rectangular box with

  • length x units (x≥0);
  • width 3 units;
  • height (8-x) units (8-x≥0, then x≤8).

The volume of the rectangular box can be calculated as

V_{box}=\text{length}\cdot \text{width}\cdot \text{height}.

In your case,  

V_{box}=3\cdot x\cdot (8-x).

Note that maximal possible value of the height can be 8 units (when x=0 - minimal possible length) and the minimal possible height can be 0 units (when x=8 - maximal possible length).

From the attached graph you can see that the greatest x-intercept is x=8, then the height will be minimal and lenght will be maximal.

Then the volume will be V=0 (minimal).

Answer: correct choices are B (the maximum possible length), C (the minimum possible height)

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Law of sines can be used to solve this problem:

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1. set up proportion.
sin 90°/25 = sin 55<span>°/x

2. solve.
(x) sin 90</span>° = (25) sin 55<span>°

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x = 20.4788011072
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3 years ago
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Anettt [7]
I think its c. Not really sure but yeah
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If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f
Anni [7]

Answer:

Part A) Annual \$66,480.95  

Part B) Semiannual \$66,862.38  

Part C) Monthly \$67,195.44  

Part D) Daily \$67,261.54  

Step-by-step explanation:

we know that

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

so

Part A) Annual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=1  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{1})^{1*5}  

A=\$47,400(1.07)^{5}  

A=\$66,480.95  

Part B) Semiannual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=2  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{2})^{2*5}  

A=\$47,400(1.035)^{10}  

A=\$66,862.38  

Part C) Monthly

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=12  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{12})^{12*5}  

A=\$47,400(1.0058)^{60}  

A=\$67,195.44  

Part D) Daily

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=365  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{365})^{365*5}  

A=\$47,400(1.0002)^{1,825}  

A=\$67,261.54  

8 0
3 years ago
Two fair dice, one blue and one red, are tossed, and the up face on each die is recorded. Define the following events:
ZanzabumX [31]

Answer:

Step-by-step explanation:

Given that two fair dice, one blue and one red, are tossed, and the up face on each die is recorded.

a) P(E) = P(the difference of the numbers is 3 or more}

Favourable events are (1,4) (1,5)(1,6) (2,5) (2,6) (3,6) (4,1) (5,1) (5,2) (6,1) (6,2)(6,3)

P(E) = \frac{12}{36} =\frac{1}{3}

b)P(F)

Favourable events for F = (1,1) (2,2)...(6,6)

P(F) = \frac{6}{36} =\frac{1}{6}

c) P(EF)

There is no common element between E and F

P(EF) =0

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Answer:

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Since this is a rectangle, the parallel sides are equal to each other, meaning we technically already know all the side lengths.

I'll choose to look at the bottom triangle in this case

30 is already there, and the other leg should be 20. Knowing this, we can plug these into the pythagorean theorem.

20 is A, 30 is B, and the missing side is C

a^{2} + b^{2} = c^{2}\\20^{2}  + 30^{2} = c^{2} \\400 + 900 = 1300 \\\sqrt{1300} = 36.06\\

C, the missing side to the nearest tenth is 36.1 meters

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