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ZanzabumX [31]
3 years ago
11

What is the domain of the function mc022-1.j pg? mc022-2.jp g mc022-3.jp g mc022-4.jp g mc022-5.jp g

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

0\leq x < infinite

Step-by-step explanation:

we have

y=\sqrt{x} +4

Find out the domain

we know that

The radicand must be greater than or equal to zero

so

x\geq 0

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to zero

0\leq x < infinite

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HA<br> 1) Simplify the expression.<br> 9 - 5*4 + 3
AysviL [449]

Answer:

Step-by-step explanation:

9-5*4+3

9-20+3

-11+3

= -8

3 0
3 years ago
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GREYUIT [131]
D'ou know the area of a circle?
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2. John and Jen went to the farmers market to buy fruit. John bought 3 boxes of oranges and 9 boxes of cherries for $78. Jen bou
jenyasd209 [6]

Answer:

Let the cost of orange be X and cost of cherry be y

3x + 9y = 78

8x + 4y = 58

Solving equation using elimination method

multiplying eq 1 with 8 and eq 2 with 3

8(3x + 9y ) = 78(8)

3( 8x + 4y) = 3(58)

24x + 72 y = 624

24x + 12y = 174

subtracting,

60 y = 450

y = 7.5

3x + 9(7.5) = 78

3x + 67.5 = 78

3x = 78 - 67.5

3x = 10.5

x = 3.5

<h2>Box of orange = $3.5 </h2><h2>Box of cherry = $7.5</h2>
7 0
2 years ago
Solve the polynomial inequality x^2-3x-10&gt;0
djverab [1.8K]

As x² - 3x - 10 factors, we can use the zero product property and pull it apart into factors. It factors because 2 and 5 have a difference of 3 and product of 10

x² - 3x - 10 > 0

(x - 5)(x + 2) > 0

To find where the inequality is true, we use a sign test. When x-5 > 0, it means x >5, and 5 is one of our sign test values. Similarly, -2 is the other. We can then make three intervals - A (less than -2), B (between -2 and 5), and C (more than 5).

<--------------- -2 ------------------ 5 -------------------------->

A B C

To do a sign test, we choose values to see what happens. First, test x = -5.

(-5 - 5)(-5 + 2) = (-10)(-3) = 30. Because 30 > 0, the inequality is true for x < -2. So interval A is true.

Next, test x = 0.

(0 - 5) (0 + 2) = (-5)(2) = -10. Because -10 < 0 is false, the inequality is false for x > -2 and x < 5. So interval B is false.

Last, test x = 10

(10 - 5) (10 + 2) = (5) (8) = 40. Because 40 > 0 is true, the inequality is true for x > 5. So interval C is true.

We put the true intervals together.

(-∞, -2) ∪ (5, ∞) is where this inequality is true,

{x : x < -2 or x > 5} is also how it's said in set notation.

7 0
3 years ago
Help me solve this equation
klio [65]

Answer:

9 is the value of a in the equation

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