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ZanzabumX [31]
3 years ago
11

What is the domain of the function mc022-1.j pg? mc022-2.jp g mc022-3.jp g mc022-4.jp g mc022-5.jp g

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

0\leq x < infinite

Step-by-step explanation:

we have

y=\sqrt{x} +4

Find out the domain

we know that

The radicand must be greater than or equal to zero

so

x\geq 0

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to zero

0\leq x < infinite

You might be interested in
Help with these precalculus problems, please.
likoan [24]
Yay, easy peasy, nice refresher


53. evaluate for x=infinity
we get 100/(infiniy^2-5) which is basically 100/infinity which is a very small number so about 0



54.
vertical assemtotes, neato
that is where the denomenator equals 0
but wait, simplify first
ok, fraction is simplified (anything factored out would be a hole)
so set the denom to 0 and solve
x^2-5=0
(x-√5)(x+√5)=0
x=-√5 and √5
vertical assemtotes at x=-√5 and x=√5




55. horizontal assemtotes
for the function p(x)/f(x)

if p(x) has lower degree than f(x) then y=0 is the horizontal assemtote

if p(x) has equal degree to f(x) then divide the leading coefients of p(x) and f(x)

if p(x) has greater degree than f(x) then we got slant assemtotes

100/(x^2-5)
100 has lower degree than x^2
y=0 is the horizontal assemtote



56. evalate for x=-5
we get -150/-10=150/10=15
the limit is 15



57. that negative on the right side means that we must approach it from the left
let's see if we can factor out the denomenator
nope
so go and evaluate values like 4, 4.5, 4.9, etc, approaching x=5 from the left
we keep getting smaller and smaller valuse
this make sense because as x approaches 5, we get 30(c)/(c-5) where c is close to 5, and as c appraoches 5 very close, the top part is appraoching 150 but the bottom approaches a very small negative number, and if we do something like 150/-0.00000000001, we get a very negative number
the limit is negative infinity

alternately, you could figure that there is a vertical assemtote at x=5 so we can see that if we aproximaate closer and closer values, we get smaller values. so from what we know about assemtotes, expecially vertical ones, we say that it approaches negative infinity




58.
evalauating we get infintity/inifinty, not helpful
hmmm, is there a horizontal assemtote to help us?
the degree of top is higher so we got a slant assemtote
the only way is to use long division to divide the top by the bottom (see attachment)
we get
\frac{1}{2}x-\frac{1}{4}+\frac{\frac{1}{4}}{2x+1}
the slant assemtote is y=\frac{1}{2}x-\frac{1}{4}
as you can see, as x approaches infinity, y also will approach infinity











ANSWERS:
53. 0
54. VA is x=-√5 and x=√5
55. HA is y=0
56. the limit is 15
57. the limit is -∞
58. the limit is ∞

6 0
3 years ago
Can someone write −4 and (6, 4) in standard form. -4 is the slope. I need it as one answer.
steposvetlana [31]

Answer:

y = -4x + 28

Step-by-step explanation:

yeah-ya........ right?

5 0
3 years ago
Read 2 more answers
debbie is making bows that use 1/6 yards of ribbion each, if debbie has 2 yards of ribbion, how many bows can she make? write a
Bezzdna [24]

Answer:

She can make 12 bows ......................................

3 0
3 years ago
F(6)=2^6 what does f equal?
Korolek [52]
F(6)=2^6
F=2^6
The answer is 
F=64
7 0
3 years ago
12. A rug has an area of 48 square feet. If it
eduard
The width is 6

length x width = area

8 x ? = 48

48/8= 6
5 0
3 years ago
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