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3 years ago

15

Miguel is a cartoonist. Miguel drew 2 cartoon cells in 3 hours. If he keeps drawing at the same rate, about how many cells will

he draw in 9 hours?

2 answers:

Art [367]3 years ago

7 0

Cross multiply and solve for x. 2/3 = x/9

Sonja [21]3 years ago

4 0

In three hours Miguel drew 2 cartoon cells . And since he keeps drawing at the same rate, therefore,

in one hour Miguel drew (2/3) cartoon cells .

Hence in 9 hours, Miguel drew (2/3)* 9 = 18/3=6 cartoon cells .

So the answer of the given question is 6 cartoon cells .

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If O is an angle in standard position and its terminal side passes through the point

Nataliya [291]

Answer:

-1/3

Step-by-step explanation:

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2 years ago

4 there are only red sweets and yellow sweets in a bag.

Taya2010 [7]

Using the probability concept, it is found that since the number of red sweets would be a decimal number, the probability cannot be $\dfrac{7}{10}$

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

In this problem:

In total, there are 8 + n sweets in the bag.

Of those, n are red.

The probability of red is:

$p=\dfrac{n}{n+8}$

Supposing, we solve for n:

$\dfrac{n}{n+8} = \dfrac{7}{10}$

10n = 7n + 56

3n = 56

n = 56 / 3

n = 18.67

Since the number of red sweets would be a decimal number, the probability cannot be 7 / 10

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2 years ago

Find the area of each composite figure. Show ALL formulas required to solve and label the answer.

mafiozo [28]

The one on the left is 6 (1/2x3x4) and the one on the right is 72 (6x12)

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2 years ago

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20% of a restaurant customers order the chef’s special. 230 customers are anticipated to dine at the restaurant tonight. The sta

Serga [27]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

2 years ago