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sladkih [1.3K]
3 years ago
10

HELP asap pls, first right=brainliest

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
4 0

Answer:

Your answer would be A:12

Step-by-step explanation:

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I think it shifts horizontally by 7 units to the right. Not completely sure though.

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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4 0
2 years ago
g Given the system of equations: 15 c1 – 5 c2 – c3 = 2400 - 5 c1 + 18 c2 – 6 c3 = 3500 - 4 c1 - c2 + 12 c3 = 4000 (a) Calculate
denpristay [2]

Answer

(a)

A^{-1} = \frac{1}{3493}  \begin{pmatrix} 210 && -59 && -12 \\ 84 && 176 && 95 \\ 77 && -5 && 295 \end{pmatrix}

(b)

A^{-1} b = \begin{pmatrix} \frac{500}{7} \\\\ \frac{2400}{7} \\\\ \frac{2700}{7} \end{pmatrix}

Step-by-step explanation:

Remember that when you want to solve a problem like this, you express the equation as following

Ax = b

So, if you know the inverse of   A   then

x = A^{-1} b

For this case

A = \begin{pmatrix} 15 &&  5 && -1 \\ -5 && 18 && -6 \\ -4 && -1 && 12  \end{pmatrix}

Now for this case the inverse of A would be

A^{-1} = \frac{1}{3493}  \begin{pmatrix} 210 && -59 && -12 \\ 84 && 176 && 95 \\ 77 && -5 && 295 \end{pmatrix}

Then when you multiply with the vector solution

A^{-1} b =  \frac{1}{3493}  \begin{pmatrix} 210 && -59 && -12 \\ 84 && 176 && 95 \\ 77 && -5 && 295 \end{pmatrix} * \begin{pmatrix} 2400 \\ 3500 \\ 4000 \end{pmatrix} = \frac{1}{3493}  \begin{pmatrix} 249500 \\ 1197600 \\ 1347300 \end{pmatrix}\\\\\\= \begin{pmatrix} \frac{500}{7} \\\\ \frac{2400}{7} \\\\ \frac{2700}{7} \end{pmatrix}

So from that information you can conclude that  the solution to the system of equations is  x = 500/7   y = 2400/7  and z = 2700/7

7 0
3 years ago
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