D. Reply.
<u><em>Brainiest PLEASE!
</em></u>
Answer:
The function is as follows:
void readAndConvert(){
int n; string symbol,name;
cin>>n;
cin>>symbol;
cin.ignore();
getline (cin,name);
vector<string> trades;
string trade;
for (int inps = 0; inps < n; inps++){
getline (cin,trade);
trades.push_back(trade);}
cout<<name<<" ("<<symbol<<")"<<endl;
for (int itr = 0; itr < n; itr++){
string splittrade[3]; int k = 0;
for(int j=0;j<trades.at(itr).length();j++){
splittrade[k] += trades.at(itr)[j];
if(trades.at(itr)[j] == ' '){
k++; }}
cout<<splittrade[2]<<": "<<floor(stod(splittrade[1]) * stod(splittrade[0]))<<endl; }
}
Explanation:
See attachment for complete program where comments are used to explain each line
Answer:
If it on g mail you go to the spam box and then press the spammers to account and then press block and then you will block them.
Answer:
The program in QBasic is as follows;
PRINT "Number: "
INPUT N
LET FACT = 1
FOR I = 1 TO N
FACT = FACT * I
NEXT I
PRINT FACT
END
Explanation:
This prompts user for number
PRINT "Number: "
This accepts input from the user
INPUT N
This initializes the factorial to 1
LET FACT = 1
This iterates through the number the user inputs and calculates its factorial
<em>FOR I = 1 TO N
</em>
<em> FACT = FACT * I
</em>
<em>NEXT I
</em>
This prints the factorial
PRINT FACT
The program ends here
END
B. Is used
If this is not the full statement it may be C
