Answer: LDX copies the instruction pointed by the memory location into the accumulator. STAA stores the content of the accumulator in the memory location $
Explanation:
Here in LDA #$2000, copies the instruction pointed by the memory location $2000 into the Accumulator A, and it uses indirect addressing.
STA $60,X stores the content of A into the memory location assigned by $60 and assigns it to X.
Answer:
"64" is the output of the above code.
Explanation:
- The function holds the expression with (**) operator which is used to calculate the power in python language.
- So if we write 2**4, then this will give 16 as output. It is because when we calculate the , then it will become 16.
- The above question passes the num1 and num2 value in the function as an argument which is 3 and 4.
- So 3 will be initialized for x variable and 4 is for y variable.
- So when we calculate then it will become which will become 16.
- So 64 is the output for the above question.
<u><em>Answer:</em></u>
<u><em>The speed is </em></u>
<u><em>=
</em></u>
<u><em>30
</em></u>
<u><em>m
</em></u>
<u><em>s
</em></u>
<u><em>−
</em></u>
<u><em>1
</em></u>
<u><em>
</em></u>
<u><em>Explanation:
</em></u>
<u><em>The speed of a wave is given by
</em></u>
<u><em>
</em></u>
<u><em>speed
</em></u>
<u><em>(
</em></u>
<u><em>m
</em></u>
<u><em>s
</em></u>
<u><em>−
</em></u>
<u><em>1
</em></u>
<u><em>)
</em></u>
<u><em>=
</em></u>
<u><em>frequency(Hz)
</em></u>
<u><em>×
</em></u>
<u><em>wavelength (m)
</em></u>
<u><em>
</em></u>
<u><em>The frequency is </em></u>
<u><em>f
</em></u>
<u><em>=
</em></u>
<u><em>100
</em></u>
<u><em>H
</em></u>
<u><em>z
</em></u>
<u><em>
</em></u>
<u><em>The wavelength is </em></u>
<u><em>λ
</em></u>
<u><em>=
</em></u>
<u><em>0.3
</em></u>
<u><em>m
</em></u>
<u><em>
</em></u>
<u><em>The speed is
</em></u>
<u><em>
</em></u>
<u><em>v
</em></u>
<u><em>=
</em></u>
<u><em>λ
</em></u>
<u><em>f
</em></u>
<u><em>=
</em></u>
<u><em>0.3
</em></u>
<u><em>⋅
</em></u>
<u><em>100
</em></u>
<u><em>=
</em></u>
<u><em>30
</em></u>
<u><em>m
</em></u>
<u><em>s
</em></u>
<u><em>−
</em></u>
<u><em>1
</em></u>
<u><em>
</em></u>
<u><em></em></u>
<u><em></em></u>
<u><em></em></u>