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3 years ago

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Find the approximate value of the circumference of a circle with the given radius. use = 3.14. round your results to one more de

cimal than in the given radius.4 inchesc =

1 answer:

sveta [45]3 years ago

4 0

The circumference of the circle is about 25.12 inches. Hope it help!

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Help please, i really need this

Licemer1 [7]

Answer:

i think a

Step-by-step explanation:

4 0

3 years ago

You and your friend have agreed to do a job which pays $200 total. If you and your friend together complete 1/4 of the overall j

butalik [34]

Answer:

If you and your friend are splitting a 200 dollar job, the answer would be 25$

Step-by-step explanation:

So, divide 200 by 4

You will get 50

Then divide 50 by 2

This gives you the answer of 25

So each friend will get 25 dollars for completing 1/4th of the job

Hope this is correct and helps!

5 0

3 years ago

Read 2 more answers

How likely is it that you would push a green button if your eyes are closed

Harrizon [31]

Answer:

This really depends on the situation, and many variables. Is there a specific moment? Multiple buttons? Would you mind giving more context or is that it?

8 0

2 years ago

Read 2 more answers

Investigate the difference between compounding annually and simple interest

Gennadij [26K]

Step-by-step explanation:

Simple interest formula

$A = P (1 + rt)$

Compound interest formula

$A = P(1 + \frac{r}{n})^{nt}$

a.

$A = 5000 (1 + 0.025*1)\\A=5000(1.025)\\A=5125$

Simple interest is $125

b

. $A = 5000 (1 + \frac{0.025}{1})^{1*1} \\A=5000(1.025)\\A= 5125$

Compound interest is $125

c. the result for both a and b are the same

d.

$A = 5000 (1 + 0.025*3) \\A=5000(1.075) \\A=5375$

the simple interest is $375

e

. $A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385$

the compound interest is $385

f. the result compared, compound interest is $10 more than simple interest

g.

$A = 5000 (1 + 0.02*6) \\A=5000(1.12) \\A=5600$

the simple interest is $600

h.

$A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869$

the compound interest is $4869

i. the result from g and h, h is over 8 times bigger than g.

j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h

6 0

3 years ago

Casper bought some pencils at .50 each. He had $3 left after the purchase. If he wanted to buy the same number of note pads at .

Nesterboy [21]

<u>Answer: </u>

Required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

<u>Solution: </u>

Let’s assume number of pencils purchased by Casper = x

As given price of each pencil is 0.50 , so price of x pencils = 0.50x = 0.5x

Also given that she was left with $3 after buying x pencils.

So initial amount which was with casper = price of x pencils + amount he was left with.

=> Initial amount with Casper = 0.5x + 3 ------(1)

Now consider second scenario

If Casper wanted to buy same number of notepad at price of 0.80 each , then

Total amount need for x notepad = 0.80x = 0.8x

But its also given that he will be short of $1.5.

So initial amount with Casper = 0.80x – 1.5 ------(2)

On equating initial amount with casper using equation (1) and equation(2) we get

0.5x + 3 = 0.8x – 1.5

=> 0.8x – 0.5x = 3 + 1.5

=> 0.3x = 4.5

=> 0.3x – 4.5 = 0

=> 3x – 45 = 0

So linear equation for x that is number of pencils he purchased is 3x – 45 = 0 where variable x represents number of pencils.

On solving the linear equation 3x – 45 = 0 for x we get

3x = 45

x = 15

Hence required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

7 0

3 years ago