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marishachu [46]
3 years ago
9

Evaluate the problem -3-(+4)

Mathematics
2 answers:
FrozenT [24]3 years ago
4 0
First you remove the parenthesis then you subtract both number and the answer is x=-7
Tcecarenko [31]3 years ago
3 0

Answer:

-7

Step-by-step explanation:

-3 - (4) = ?

Remove parentheses:

=  -3 - 4

Subtract the numbers:

= -7

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QUICK !!!<br> What is the image point of (-8,0) after a reflection over the y-axis ?
kondor19780726 [428]

Answer:

0, 8

Step-by-step explanation:

A reflection is the opposite direction so, if it's eight units to the left, the reflection will be eight units to the right, and we know the right is positive and left is negative.

4 0
3 years ago
Is the following a function ?
Vanyuwa [196]
Yes it is a function
6 0
3 years ago
If your grade is 68.27 and you get a 15 out of 15 on your test whats your grade now
mixer [17]

Answer:

84

Step-by-step explanation:

68 + 100 = 168

168/2 = 84

8 0
2 years ago
Find the gcf and lcm of 10and15
Murrr4er [49]
The greatest common factor of 10 is 10 and the least common factor of 15 is 15
Hope I helped!!!!!
3 0
3 years ago
Find a power series representation of e^x sin(x)
liberstina [14]
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
6 0
3 years ago
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