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Arisa [49]
3 years ago
5

Two different types of cake are on sale at prices of $0.30 and $0.40 each. The cakes that are being sold for $0.30 cost $0.20 to

make and the ones for sale at $0.40 cost $0.25 to make. No cakes can be kept to be sold the next day, so all of the cakes are reduced to half price 2 hours before the sales finish. All of the $0.30 cakes sold out before any of the prices were reduced, and all of the $0.40 were eventually sold, even though only half had been sold when the price was reduced. The overall profit at the end of the day was $30.00, but it could have been $40.00 if all of the cakes had sold before the prices were reduced. How many of each type of cake were there in the sale?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

30.00=100 cakes

40.00=100 cakes

Step-by-step explanation:

30.00/.30=100

40.00/.40=100

( i think im sorry if this is wrong)

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THIS IS THE LAST QUESTION IDK HOW DO SOLVE IT :(
harkovskaia [24]

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6 laps.

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4 0
3 years ago
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Marina86 [1]

Answer:

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Step-by-step explanation:

The key understanding here is that you can factor a monomial in many different ways!

To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x

7

12, x, start superscript, 7, end superscript.

Hint #22 / 4

\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(4x

3

)(3x

4

)

​

 

=(4)(3)(x

3

)(x

4

)

=12x

7

​

So Ibuki is correct!

Hint #33 / 4

\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(2x

6

)(6x)

​

 

=(2)(6)(x

6

)(x)

=12x

7

​

So Melodie is also correct!

Both Ibuki and Melodie are correct.

8 0
3 years ago
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grandymaker [24]

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Step-by-step explanation:

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