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Yanka [14]
3 years ago
11

Please help and answer the question -Will give Brainliest

Mathematics
1 answer:
artcher [175]3 years ago
3 0
<h3>Part A</h3>

Each year, the number of cars in Cory's collection (c) increases by a factor of 1.2. After t years, it will be multiplied by that factor "t" times, so the number of cars will be ...

... c(t) = 15·1.2^t

Each year, the number of cars in Roger's collection (r) increases by 1. After t years, it will have increased by t.

... r(t) = 40 +t

<h3>Part B</h3>

c(6) = 15·1.2^6 ≈ 44.79 ≈ 45 . . . Cory's cars after 6 years

r(6) = 40 +6 = 46 . . . Roger's cars after 6 years

<h3>Part C</h3>

The number of cars is very nearly the same after 6 years. A short time into the 7th year, the number of cars will be the same. A graph shows the number of cars will be the same after about 6 years and 2 months.

There are no algebraic methods to solve the equation

... r(t) = c(t)

... 45 +t = 15·1.2^t

It can be solved by trial and error, or graphically, or by other iterative means. The solution is not an integer, but non-integer numbers of cars don't make sense. It isn't exactly clear what a solution would look like.

year 6: Cory ≈ 45 cars; Roger = 46 cars

year 7: Cory ≈ 54 cars; Roger = 47 cars

Between year 6 and year 7 (closer to the beginning of year 7), Cory will have 46 cars, about the same number Roger has at that time.

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B

Step-by-step explanation:

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3 years ago
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Solve the following system of equations. Show all work and solutions.
Hitman42 [59]
  • y=2x²+6x+1
  • y=-4x²+1

Make the equations equal and solve for x

  • 2x²+6x+1=-4x²+1
  • 6x²+6x=0
  • 6x(x+1)=0
  • 6x=0 or x+1=0
  • x=0 or x=-1

For x=0

  • y=-4(0)+1=1

For x=-1

  • y=-4(1)+1=-3

The solutions are

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Graph attached

4 0
2 years ago
Tony rode his bicycle 3 7/10 miles to school. What is this distance written as a decimal?
ollegr [7]

Answer:

7/10=0.7

3+0.7=3.7

3.7

Hope this helps

Step-by-step explanation:

4 0
2 years ago
Prove the divisibility of the following numbers:
ratelena [41]

Make use of prime factorizations:

16^5+2^{15}=(2^4)^5+2^{15}=2^{20}+2^{15}

Both terms have a common factor of 2^{15}:

16^5+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\cdot33

- - -

The second one is not true! We can write

15^7+5^{13}=(3\cdot5)^7+5^{13}=3^7\cdot5^7+5^{13}

Both terms have a common factor of 5^7:

15^7+5^{13}=5^7\left(3^7+5^6\right)

Since 30=5\cdot6, and 5\mid5^7, we'd still have to show that 5^6(3^7+5^6) is a multiple of 6. This is impossible, because 6=3\cdot2 and there is no multiple of 2 that can be factored out.

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2 years ago
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What is 15 divided by 2,345
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Is 15÷2345= 0.0063965......
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