Answer:
11.25 ft/sec
Step-by-step explanation:
Given that a jogger runs around a circular track of radius 55 ft.
. Let (x,y) be her coordinates, where the origin is the center of the track.
Then we know x,y satisfies the equation of the circle as
Let us differentiate this implicit function with respect to t
At this point, dx/dt 15 and x=33. y =44
Substitute to have
dy/dt = 11.25 ft /s
Answer:
Step-by-step explanation:
We have that
A = 51°, b = 14, c = 6
step 1
find the value of a
Applying the law of cosines
a²=c²+b²-2*c*b*cos A
a²=6²+14²-2*6*14*cos 51-------> 126.27
a=11.2
we know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
we have
a=11.2
b=14
c=6
so
(a+b) > c-------------> (11.2+14)=25.2
25.2 > 6-----> is not correct
therefore
the answer is the option
a. No triangles possible
I don't know if i am right sorry if this is wrong
Answer:
C
Step-by-step explanation:
The gradient is
So, using the y-intercept, the equation is
Answer:
-3
Step-by-step explanation:
(-6)/(+2)
-6/+2
-3
Answer:
Your question was a bit confusing so I found another related question. You can reference it with your own details.
A vendor bought 10 dozen eggs at the rate of Rs 22 per dozen. Six of the eggs were rotten. He sold the remaining eggs at the rate of Rs 2.50 per egg . Find his profit or loss
Vendor bought 10 dozen eggs which means the vendor bought:
= 10 * 12 eggs
= 120 eggs
6 were rotten and he sold the rest for Rs. 2.50 per egg.
= (120 - 6) * 2.5
= Rs. 285
The amount he spent on the eggs was:
= 10 dozen * 22
= Rs. 220
Profit = 285 - 220
= Rs. 65
