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Mars2501 [29]
2 years ago
12

Anyone good at trigonometry? need help with this question pls

Mathematics
1 answer:
kenny6666 [7]2 years ago
5 0

Answer:

which class are you which class question is this

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Which is bigger: 3/8 or 7/20
umka21 [38]
\rm ^{20)}\frac{3}{8}= \frac{60}{160}  \\ \\ ^{8)}\frac{7}{20}= \frac{56}{160} \\ \\ So~ \frac{3}{80}~is~bigger~because~60\ \textgreater \ 56.
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What is the median of the data set represented by the dot plot?
umka21 [38]

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The median is 5.

Step-by-step explanation:

To find the median you have to do steps, (they are really easy):

The median is like the middle of the graph so just try finding the middle, ( i could explain this in a different way but it's hard to explain) Hope this helps.

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What is .08333333333 as a fraction ?
madam [21]
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5 0
3 years ago
To study the output of a machine that fills boxes with cereal, a quality control engineer weighed 150 boxes of Brand X cereal. T
scoundrel [369]

Answer:

\sigma = 0.07770

Step-by-step explanation:

Given

The above table

Required

The standard deviation

First, calculate the class mid-point. This is the average of the class interval.

The mid-point x is:

x_1 = \frac{1}{2}(15.3 + 15.6) =\frac{1}{2} * 30.9 = 15.45

x_2 = \frac{1}{2}(15.6 + 15.9) =\frac{1}{2} * 31.5 = 15.75

x_3 = \frac{1}{2}(15.9 + 16.2) =\frac{1}{2} * 32.1 = 16.05

x_4 = \frac{1}{2}(16.2 + 16.5) =\frac{1}{2} * 32.7 = 16.35

x_5 = \frac{1}{2}(16.5 + 16.8) =\frac{1}{2} * 33.3 = 16.65

So, we have:

\begin{array}{cccccc}x & {15.45} & {15.75} & {16.05} & {16.35} & {16.65} \ \\ f & {14} & {25} & {84} & {18} & {9} \ \end{array}

Calculate mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{15.45 * 14 + 15.75 * 25 + 16.05 * 84 + 16.35 * 18 + 16.65 * 9}{14 + 25 + 84 + 18 + 9}

\bar x = \frac{2402.4}{150}

\bar x = 16.016

The standard deviation is:

\sigma = \sqrt{\frac{\sum(x_i - \bar x)^2}{\sum f}}

\sigma = \sqrt{\frac{(15.45 - 16.016)^2+ (15.75  - 16.016)^2+ (16.05  - 16.016)^2+ (16.35   - 16.016)^2+ (16.65  - 16.016)^2}{14 + 25 + 84 + 18 + 9}}

\sigma = \sqrt{\frac{0.90578}{150}}

\sigma = \sqrt{0.00603853333}

\sigma = 0.07770

4 0
2 years ago
​9 ×​ 10² <br> I NEED ANSWERS QUICK
garik1379 [7]
900.


Hope this helps!
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